- #1

- 27

- 0

## Homework Statement

indefinite integral 5[tex]\pi[/tex]cos[tex]\pi[/tex]t

## Homework Equations

## The Attempt at a Solution

5[tex]\pi[/tex] int cos[tex]\pi[/tex]t

Substitution Method

5[tex]\pi[/tex] x sin (1/[tex]\pi[/tex]t

- Thread starter char808
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- #1

- 27

- 0

indefinite integral 5[tex]\pi[/tex]cos[tex]\pi[/tex]t

5[tex]\pi[/tex] int cos[tex]\pi[/tex]t

Substitution Method

5[tex]\pi[/tex] x sin (1/[tex]\pi[/tex]t

- #2

Mark44

Mentor

- 34,678

- 6,387

Is this your integral?## Homework Statement

indefinite integral 5[tex]\pi[/tex]cos[tex]\pi[/tex]t

## Homework Equations

## The Attempt at a Solution

5[tex]\pi[/tex] int cos[tex]\pi[/tex]t

Substitution Method

5[tex]\pi[/tex] x sin (1/[tex]\pi[/tex]t

[tex]\int 5 \pi cos(\pi t)dt[/tex]

Click the integral above to see how the LaTeX looks.

A reasonable substitution would be u = [itex]\pi t[/itex], so du = [itex]\pi dt[/itex].

Can you take it from there?

- #3

- 27

- 0

[tex]

5 \pi sin(u)du

[/tex]

[tex]

5 \pi sin(u) x du/ \pi

[/tex]

[tex]

5sin(\pi t)

[/tex]

- #4

Mark44

Mentor

- 34,678

- 6,387

What is the first line supposed to mean?

How did you get from the first line to the second?

How did you get from the second line to the third?

Are any of these expressions related to each other in any way?

Since this is an integration problem, one would think there should be an integral sign somewhere.

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