How can I integrate this function using substitution?

[ada0713]

Homework Statement

Evaluate the definate integral of the following
\int (from 1 to 2) \frac{sin t}{t} dt

The Attempt at a Solution

I am actually stuch from the very beginning.
I tried to set u=sin(t) but this doesn't help much because (sint)'=cost and
this is going to make the problem more complicated.
I also set u=1/t but the derivative of 1/t has nothing to do with
the function as well.

(Perhaps I shouldn't integrate the function by substitution)

Please help me with the start!

 

[ada0713]

I set:
u=sint dv=1/t dt
du=-cost v=lnltl

\int [from 1 to 2] (sint)(1/t) dt

= [(sint)(lnltl)]^{1}_{2} -\int[from 1 to 2] lnltl (-cost)

How do I integrate the red part?
should I do the by parts again?

 

[rock.freak667]

Well...I do not think there is any closed form of that integral.(To my knowledge) You may need something more than integration by parts.

 

[rocomath]

For your latex

\int_1^2

\frac 1 t or \frac{1}{t} - use the brackets when you have more than one letter per term

Or maybe you were lazy

 

[Defennder]

roco, where did you learn the \int_1^2 notation? I never figured it out, at least not from the latex code reference PDF file.

 

[rocomath]

roco, where did you learn the \int_1^2 notation? I never figured it out, at least not from the latex code reference PDF file.

\int_1^2

Click on the latex and you will see the code.