Integration Help: Solve ∫sqrt(a^2-x^2)/x*sqrt(x^2-b^2)

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Homework Help Overview

The discussion revolves around the integral ∫sqrt(a^2-x^2)/x*sqrt(x^2-b^2) and the challenges faced in solving it. The subject area includes calculus, specifically integration techniques.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss various substitution attempts and express confusion about the effectiveness of certain manipulations. There is a mention of a potential relationship between the terms in the integrand, and some participants question the relevance of these insights.

Discussion Status

The discussion is ongoing, with participants sharing their attempts and questioning the utility of certain approaches. There is no clear consensus on a viable method, and some participants express frustration with the complexity of the problem.

Contextual Notes

One participant notes an edit to the original post that clarifies the expression, while another expresses doubt about the correctness of their previous work. There is a mention of a computational tool suggesting that the integral cannot be solved, adding to the uncertainty in the discussion.

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Homework Statement



[tex]\int[/tex] [tex]\sqrt{a^{2}-x^{2}}[/tex][tex]/[/tex][tex]x*\sqrt{x^{2}-b^{2}}[/tex]



The Attempt at a Solution



I tried all sorts of substitutions and none work. Please help me.
 
Last edited:
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Would it help to know that
[tex]\frac{a^2- x^2}{x^2- b^2}= \frac{b^2- a^2}{x^2- b^2}- 1[/tex]
 
Edit notice: I multiplied the integrand by 1/x. Its not to the xth root of. I didn't type that in first type.
 
I don't have a clue how that helps HallsofIvy.
 
Mathematica says this rubbish can't be solved.
 
Have you editted the first post? I didn't notice that "x" outside the square root before.
Let u= x2- b2 so that du= 2xdx
[tex]\sqrt{\frac{b^2-a^2}{x^2- b^2}-1}= \sqrt{\frac{A}{u}- 1}[/tex]
 
Yes. I edited the first post. Forget it though. I think what I did is wrong anyway.
 

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