Integration with Eulers formula.

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SUMMARY

The discussion centers on integrating the function \(\frac{e^x}{\cos(x)}\) using Euler's formula. The user begins by rewriting the expression as \(\frac{e^x}{e^{ix}}\) and proceeds to integrate, resulting in \(\frac{e^{(1-i)x}}{1-i}\). The conversation highlights the method of multiplying by the complex conjugate and back substituting \(e^{ix}\) to extract the real part. Participants confirm that it is valid to back substitute \(i\sin(x) + \cos(x)\) and then multiply by \((1-i)\) before taking the real part.

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  • Understanding of complex numbers and Euler's formula
  • Knowledge of integration techniques in calculus
  • Familiarity with complex conjugates and their properties
  • Ability to manipulate exponential functions
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  • Learn about complex conjugates and their role in integration
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cragar
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I want to integrate \frac{e^x}{cos(x)} with eulers formula.
I start by writing \frac{e^x}{e^{ix}}
then I integrate that as usual.
So after I integrate I get \frac{e^{(1-i)x}}{1-i}
Normally I would multiply and divide by the complex conjugate and then back substitute in
e^(ix) and the take the real part.

can I just back substitute in isin(x)+cos(x) on the bottom and then multiply it by (1-i)
and then take the real part. That seems to easy.
Does anyone have suggestions. This is not a homework problem.
 
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Hey cragar.

You should be able to integrate the expression and then take the real part as your answer.
 

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