- #1

- 53

- 0

## Homework Statement

(integrate)sec^3(2x)*tan(2x)dx

## Homework Equations

## The Attempt at a Solution

Okay, so first I tried to separate secant and tangent, to get (integrate)1/cos^3(2x) * sin(2x)/cos(2x)dx. The u would be cos(2x), the du would be -du=sin(2x)dx.

I subsitute these in the aforementioned equation, whcih leaves (integrate)1/u^3 x 1/u. The problem is, I don't think this is right.