Intensity of light after passing thru polaroid

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SUMMARY

The discussion focuses on the calculation of light intensity after passing through two polaroids, where one is rotated. The initial assumption is that the light is unpolarized, leading to an intensity after the first polaroid of I1 = 0.5 I0. The final intensity after the second polaroid, given by I2 = 0.5 I0 (cos θ)^2, results in an angle θ of 35.3°. However, the correct answer from the book is 54.7°, indicating a misinterpretation of the problem's phrasing regarding the reference intensity.

PREREQUISITES
  • Understanding of light polarization and intensity calculations.
  • Familiarity with the Malus's Law for light passing through polarizers.
  • Basic trigonometry for calculating angles and cosine values.
  • Knowledge of the difference between polarized and unpolarized light.
NEXT STEPS
  • Study Malus's Law in detail to understand intensity changes through polarizers.
  • Learn about the properties of polarized and unpolarized light.
  • Explore common problems involving multiple polarizers and their configurations.
  • Investigate the mathematical derivation of intensity equations for light passing through polarizers.
USEFUL FOR

Students studying optics, physics educators, and anyone interested in understanding the behavior of light through polarizing filters.

somecelxis
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Homework Statement


Two pieces of polaroid are arranged so they are initially parallel . One of the polaroid is rotated until the intensity of the light beam from the two polaroid is 1/3 of its initial intensity . Calculate the angle turned thru the polaroid


Homework Equations





The Attempt at a Solution


i assume it's a non-polarised passing thru the first polaroid , then the second polaroid is rotated.
so i have Intensity after passing thru 1st polaroid (I 1 ) = 0.5 intensity of non-polarised (I 0)...
for light ray emerging from second polaroid = (I 2 ) = 0.5(I 0) ( (cos θ )^2) .finally i found out my θ = 35.3° the ans form the book is 54.7°

why i am wrong?
the initial light ray is polarised or non- polarised? how to determine it? it's not stated in the question...
 
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somecelxis said:

Homework Statement


Two pieces of polaroid are arranged so they are initially parallel . One of the polaroid is rotated until the intensity of the light beam from the two polaroid is 1/3 of its initial intensity . Calculate the angle turned thru the polaroid


Homework Equations





The Attempt at a Solution


i assume it's a non-polarised passing thru the first polaroid , then the second polaroid is rotated.
so i have Intensity after passing thru 1st polaroid (I 1 ) = 0.5 intensity of non-polarised (I 0)...
for light ray emerging from second polaroid = (I 2 ) = 0.5(I 0) ( (cos θ )^2) .finally i found out my θ = 35.3° the ans form the book is 54.7°

why i am wrong?
the initial light ray is polarised or non- polarised? how to determine it? it's not stated in the question...

It sounds like they did not phrase the problem correctly. With the precise phrasing you wrote, you are correct (assuming initial unpolarized light). But if interpret the question as meaning: at what angle is the intensity equal to 1/3 it was before entering the second polarizer (in other words, by "initial" we mean before the second polarizer, not before the two polarizers) then we get the answer they give.
 

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