Intensity-wavelength graph for X-ray

[Titan97]

The cut-off wavelength is the minimum wavelength of the X-ray emitted. But doesn't minimum wavelength correspond to maximum energy? Why is intensity zero at minimum wavelength? Shouldn't it be maximum when wavelength is minimum since $\lambda=\frac{hc}{E}$

 

[Simon Bridge]

The cut-off wavelength is the minimum wavelength of the X-ray emitted. But doesn't minimum wavelength correspond to maximum energy?

Yes it does.

Why is intensity zero at minimum wavelength?

Because there are no x-rays emitted at that wavelength.

Shouldn't it be maximum when wavelength is minimum since $\lambda=\frac{hc}{E}$

Unless you have a special reason to think that more light will be emitted at high energies than low energies.

I think you may be getting confused between wave a particle models for light - $E=hc/\lambda$ is the energy of an individual photon - the intensity is the number of photons per unit area per unit time. The relation means that it takes fewer short-wavelength photons to produce a high intensity light.