Photon wavelength probability distribution for blackbody

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SUMMARY

The discussion focuses on modeling the photon wavelength probability distribution emitted from a blackbody at temperature T. The key formula derived is the probability density function for photon wavelengths, expressed as Prob(λ) = (1/λ⁴ * (1/(e^(hc/(λk_B T)) - 1))) divided by the integral of the same function over all wavelengths. The conversation references Planck's law for spectral radiance, which is crucial for understanding the relationship between temperature and emitted photon wavelengths. The participants confirm the correctness of the derived probability density function and its implications for photon detection.

PREREQUISITES
  • Understanding of Planck's law for spectral radiance
  • Familiarity with the concepts of photon energy and wavelength
  • Knowledge of probability density functions
  • Basic grasp of thermodynamics related to blackbody radiation
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  • Study the derivation of Planck's law in detail
  • Explore the implications of blackbody radiation in quantum mechanics
  • Learn about the integration of probability density functions in statistical mechanics
  • Investigate applications of photon wavelength distributions in spectroscopy
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Physicists, researchers in thermodynamics, and anyone interested in quantum mechanics and blackbody radiation modeling will benefit from this discussion.

Orthoptera
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Hey everyone,

This is my first time posting on PF!

I want to model the photons ejected from a blackbody source at temperature T.
The question I want answered is: given a photon is detected, what is the probability of the photon having a wavelength λ? This amounts to just attaining the probability density function for the different wavelengths.

We normally talk about blackbodies in terms of intensity, or more specifically spectral radiance, but I want to talk about the individual photon wavelength distribution.

My current thoughts are:
Plank’s law for spectral radiance as a function of wavelength may be written as :
\begin{eqnarray}
\label{plank1}
I(\lambda,T) = \frac{2 h c^2 }{\lambda^5} \frac{1 }{e^{\frac{hc}{\lambda k_B T}}-1}
\end{eqnarray}
where I is the spectral radiance, the power radiated per unit area of emitting surface in the normal direction per unit solid angle per unit frequency by a black body at temperature T, h is Plank’s constant, c is the speed of light in a vacuum and k is the Boltzmann constant. The energy produced by a single wavelength of light is
\begin{eqnarray}
\label{plank15}
E=N_\lambda h c / \lambda
\end{eqnarray}
where N is the number of photons at this wavelength produced by the blackbody. It follows from Plank’s law that the number of photons produced by a blackbody with a certain wavelength follows the proportionality:
\begin{eqnarray}
\label{plank2}
N_\lambda(\lambda,T) \propto \frac{1}{\lambda^4} \frac{1 }{e^{\frac{hc}{\lambda k_B T}}-1}
\end{eqnarray}
Then the probability density of a blackbody emitting a photon of wavelength λ is given by normalising:
\begin{eqnarray}
\label{plank3}
Prob(\lambda)= \frac{\frac{1}{\lambda^4} \frac{1 }{e^{\frac{hc}{\lambda k_B T}}-1}}
{\int_{0}^{\infty} \frac{1}{\lambda^{\prime^4}} \frac{1 }{e^{\frac{hc}{\lambda^\prime k_B T}}-1} d\lambda^\prime}
\end{eqnarray}

Any thoughts on whether this is right?

Peter.
 
Last edited:
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That is almost correct. The probability that the wavelength ## \lambda ## obeys ## \lambda_1 < \lambda \leq \lambda_1 +\Delta \lambda ## is given by ## Prob(\lambda_1) \Delta \lambda ## for small ## \Delta \lambda ##, and where ## Prob(\lambda) ## is as you defined it above.
 

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