Interesting Linear Algebra Problem

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Homework Help Overview

The problem involves three column vectors in R3, specifically x=(1,0,0), y=(2,1,0), and z=(2,2,1). The original poster is exploring the set V defined by linear combinations of these vectors with specific constraints on the coefficients.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to visualize the geometric representation of the set V, suggesting it may fill a solid shape formed by the vectors. Other participants discuss the implications of linear independence on the dimensionality of the set V.

Discussion Status

Participants are engaged in exploring the geometric interpretation of the vectors and their linear combinations. There is a shared understanding that the vectors are linearly independent, and some participants confirm the original poster's visualization of the space filled by the vectors.

Contextual Notes

There is an ongoing discussion about the dimensionality of the set V based on the linear independence of the vectors, as well as the specific geometric shape that the set represents.

Newtime
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Homework Statement



Let x=(1,0,0) y=(2,1,0) and z=(2,2,1) be column vectors in R3. Consider the set V={tx+sy+uz 0[tex]\leq[/tex]t,s,u[tex]\leq[/tex]1}. What does this look like specifically?

Homework Equations



n/a

The Attempt at a Solution



No work here, just a thinking problem, but I thought that the set V would fill the solid (a paralellapipid?) formed by the three vectors x,y, and z. Is this correct? Other than visualization, I suppose a reason for this would be that it is analagous to a similar problem in R2 in which the set vills the parallelogram formed by the two vectors. Thanks.
 
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If the given vectors were linearly independent, set V would be a three-D region in space, but if they are linearly dependent V will be only a one- or two-dimensional subset of R3.
 
Mark44 said:
If the given vectors were linearly independent, set V would be a three-D region in space, but if they are linearly dependent V will be only a one- or two-dimensional subset of R3.

They are linearly independent. And I know they fill some space in R3 but the question was which space...as into describe it. So my best explanation is the vectors fill the paralellepiped formed by the three vectors. Isn't this correct?
 
Newtime said:
They are linearly independent. And I know they fill some space in R3 but the question was which space...as into describe it. So my best explanation is the vectors fill the paralellepiped formed by the three vectors. Isn't this correct?

Yes, you are visualizing it correctly.
 
Dick said:
Yes, you are visualizing it correctly.

Thanks, I figured I was but wanted to check with all the gurus here.
 

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