Interference - Q done, is it right?

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The discussion revolves around verifying calculations related to wave interference, specifically the wavelength and frequency of a sound wave. The original poster calculated the distance as d = √17 and derived the wavelength λ = 0.698m, leading to a frequency of f = 487 Hz. However, they acknowledged making errors in their calculations and received clarification that the formula for frequency should account for multiple harmonics. The correct approach involves using the formula f = (2n-1)v/2d for various integer values of n. The conversation emphasizes the importance of accuracy in wave interference calculations.
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Hi all, I have a question here that I've done but it hasn't got an answer provided. I'm sure it's easy stuff but haven't looked at this material in a while so
just want to double check.

(The things in red are what I added to the original diagram)

intereferenceexampleQ.jpg


RE-DONE

d = √17

d + λ/2 = 2√5

λ/2 = 2√5 -d

λ = 4√5 -2(√17)

λ = 0.698m

Using v=fλ

∴f = 340/0.698 = 487 Hz

Is this correct?

Thanks in advance
 
Last edited:
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d=\sqrt{1^2+4^2}=\sqrt{17}
 
szynkasz said:
d=\sqrt{1^2+4^2}=\sqrt{17}

Woops, muppet at work. No idea how that came about, thanks.

Looking over it I've done a couple of very stupid errors such as line 4.

First post RE-DONE
 
Last edited:
Correct, but you get more frequencies:

(2n-1)\frac{\lambda}{2}=d\Rightarrow f=(2n-1)\frac{v}{2d},\,n=1,2,3,...
 
szynkasz said:
Correct, but you get more frequencies:

(2n-1)\frac{\lambda}{2}=d\Rightarrow f=(2n-1)\frac{v}{2d},\,n=1,2,3,...

Thanks a lot, big help
 
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