Internal half of the fresnel zone

In summary, the question asks about the light intensity on an opaque screen with a circular hole when a plane monochromatic light wave is incident normally. Two cases are considered: when the hole is the first Fresnel zone and when it is made equal to the first zone and then shut down by half in diameter. The inner half of the first zone is mentioned, and there is no mention of an outer half. A hint is provided with a link to the Wikipedia page on Fresnel zones.
  • #1
harrydj
1
0

Homework Statement


Plane monochromatic light wave with intensity I 0 is incident normally on an opaque screen with a circular hole. What is the light intensity I of the screen at the point for which the hole:
a) is the first Fresnel zone, the inner half of the first zone,
b) made ​​equal to the first Fresnel zone, and then shut it down half (diameter)?


Homework Equations



Here What is the inner half of the first zone? Is there any outer half for the first zone.

The Attempt at a Solution

 
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  • #2
harrydj said:

Homework Statement


Plane monochromatic light wave with intensity I 0 is incident normally on an opaque screen with a circular hole. What is the light intensity I of the screen at the point for which the hole:
a) is the first Fresnel zone, the inner half of the first zone,
b) made ​​equal to the first Fresnel zone, and then shut it down half (diameter)?


Homework Equations



Here What is the inner half of the first zone? Is there any outer half for the first zone.

The Attempt at a Solution


Hint: http://en.wikipedia.org/wiki/Fresnel_zone

What do you notice from here ?
 

1. What is the internal half of the Fresnel zone?

The internal half of the Fresnel zone is a theoretical region in space surrounding an antenna that affects the propagation of radio waves. It is a critical consideration for wireless communication systems, as it can impact signal strength and quality.

2. How does the internal half of the Fresnel zone affect wireless communication?

The internal half of the Fresnel zone can cause diffraction and reflection of radio waves, which can lead to interference and signal degradation. This can result in poor signal strength, dropped calls, and slow data speeds.

3. What factors affect the size of the internal half of the Fresnel zone?

The size of the internal half of the Fresnel zone is affected by the frequency of the radio waves, the distance between the transmitting and receiving antennas, and any obstacles or terrain between them. Higher frequencies and longer distances result in a larger Fresnel zone, while obstacles can decrease its size.

4. How can the internal half of the Fresnel zone be calculated?

The internal half of the Fresnel zone can be calculated using the following formula: D = 0.6 * √(λ * d1 * d2), where D is the radius of the zone, λ is the wavelength of the radio waves, and d1 and d2 are the distances from the antennas to the point of interest. There are also online calculators and software programs available for more precise calculations.

5. How can the internal half of the Fresnel zone be managed in wireless communication systems?

To manage the impact of the internal half of the Fresnel zone on wireless communication, it is important to ensure that there are no obstacles or obstructions within the zone. This can be achieved by carefully planning the placement of antennas and conducting regular maintenance to clear any potential obstacles. Additionally, using higher frequencies or increasing the height of antennas can also help to mitigate the effects of the Fresnel zone.

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