An emergency supply consists of a small diesel engine driving an alternator. The output of the alternator is rectified and smoothed to produce DC. This has has to supply 10 amps of 110V emergency lighting and charge a 110V battery of internal resistance 2 ohms,
If the supply system has an internal resistance of 1 ohm calculate the minimum output voltage in order to just start charging the 110V battery.
V = IR
Kirchoffs current and voltage laws
The Attempt at a Solution
I am strugggling to understand the above statement and put it into a circuit diagram. I have attempted (see the attached jpg). Am I right in thinking the lamp has 11ohm resistance (110V/10A). Therefore total circuit resistance is 1/(1/1 + 1/11 + 1/2) = 0.629 ohms. Then can I go on to use simultaneous equations. Or am I looking too deep into this.
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