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## Homework Statement

a family consisting of a father, mother, and a child is chosen at random and is asked on what day of the week each of them was born. What is the probability that all three were born on different days given that the father was born on a monday?Solution: A is the even all three were born on different days. B is the event that the father was born on a monday. n(A and B)=6P2=30 and n(B)=7*7=49. So P(A|B)=30/49

## Homework Equations

P(A|B)=P(A and B)/P(B).

P(A|B) reads: probability of A given B.

## The Attempt at a Solution

Really, what i dont get is why for n(B), we get 7*7. I mean it should be 52 since there are 52 weeks in a year=>52 mondays in a year. I just don't get the solution that was given.