Interpretation of the Van der Waals Equation

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Discussion Overview

The discussion revolves around the interpretation of the Van der Waals (VDW) equation, specifically the reasoning behind the modifications made to pressure and volume when transitioning from the ideal gas law to the VDW equation. Participants explore the implications of the terms in the equation and seek intuitive explanations for these adjustments.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • One participant questions why the volume is adjusted by subtracting "b" while the pressure is adjusted by adding "a/V^2" in the VDW equation, seeking an intuitive understanding of this approach.
  • Another participant mentions a formal method to demonstrate that the "a" term represents an attractive force using the virial expansion but admits to lacking an intuitive explanation.
  • A third participant provides a clarification that in the VDW equation, "V" represents the ideal gas volume (the volume of the container), while "P" represents the real gas pressure, which is influenced by the attractive forces and the finite size of molecules.
  • This participant outlines a derivation from the ideal gas law to the VDW equation, indicating how the real gas pressure is derived from the ideal gas volume adjusted for the finite size of molecules and attractive forces.

Areas of Agreement / Disagreement

Participants express varying levels of understanding regarding the intuitive aspects of the VDW equation. While some provide clarifications and derivations, no consensus is reached on a singular intuitive explanation for the adjustments made to pressure and volume.

Contextual Notes

Some participants reference formal methods and external resources for deeper understanding, indicating that there may be limitations in the intuitive explanations provided within the discussion.

nezahualcoyot
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There is a silly detail about the interpretation of the Van der Waals (VDW) equation that I cannot fully understand. Say we have the Van der Waals equation for one mole:

(P + a / V^2 ) (V - b) = RT

The usual interpretation is that if you start from the ideal gas law PV=RT, you have to "decrease" the volume to take into account the finite size of molecules, so you replace "V" by "V-b". The attractive forces also reduce the pressure, so you... replace "p" by "p+a/V^2 " ? Why not "p-a/V^2 " ? Why if both pressure and volume are reduced, you subtract a quantity to volume but add a quantity to pressure? I know the equation is correct as it reproduces experimental results within its domain of applicability, but I would like an intuitive explanation for this. Thanks!
 
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There is a formal way to see that the "a" term does indeed represent an attractive force, by using the virial expansion. However, I don't know an intuitive explanation to supplement the formal way. Kardar's notes http://ocw.mit.edu/courses/physics/8-333-statistical-mechanics-i-statistical-mechanics-of-particles-fall-2007/lecture-notes/lec17.pdf give the formal way and some explanations which are supposed to be intuitive, but I don't understand the latter.

(Kardar's full set of notes is at http://ocw.mit.edu/courses/physics/8-333-statistical-mechanics-i-statistical-mechanics-of-particles-fall-2007/lecture-notes/ .)
 
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Thank you atyy. I got an answer for my question elsewhere. Its basically that, in the VDW equation, "V" stands for the ideal gas volume, as this is the quantity you measure experimentally (the volume of the container), but "P" stands for the real gas pressure, as this is what you measure.

To derive VDW from the ideal gas law, P = RT/V, the real gas pressure "P" will depend on the real gas volume, which is the ideal gas volume "V" minus a factor, so you have

P = RT/(V-b)

Finally you must subtract a factor from the real pressure to account for the attractive forces, so you get

P = RT/(V-b) - a/V^2

which is the VDW equation (P + a / V^2 ) (V - b) = RT.
 
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Thanks!
 

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