Compressibility factor and van der Waals equation for temp

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Discussion Overview

The discussion revolves around the compressibility factor (z) of real gases as described by the van der Waals equation, particularly focusing on how temperature affects this factor. Participants explore the relationship between temperature, pressure, and volume in the context of real gases compared to ideal gases, with an emphasis on mathematical modeling and numerical solutions.

Discussion Character

  • Exploratory
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant notes that the pressure exerted by a real gas is lower than that of an ideal gas due to intermolecular attractive forces and suggests that the compressibility factor z decreases at lower temperatures.
  • The same participant expresses difficulty in using the van der Waals equation to demonstrate this relationship and seeks assistance in evaluating volumes at different temperatures.
  • Another participant proposes numerically solving the van der Waals cubic equation for volume (V) and suggests that if multiple real solutions exist, the correct one can be chosen based on simpler equations of state (EOS) like the Ideal Gas Law.
  • A repeated suggestion emphasizes the potential for plotting compressibility factor values against temperature using calculated volumes from varying temperatures.
  • There is a question raised about whether decreasing temperature would result in the compressibility factor falling below 1 more significantly than at higher temperatures.

Areas of Agreement / Disagreement

Participants express similar ideas regarding the numerical solution of the van der Waals equation and the relationship between temperature and compressibility factor. However, the discussion remains unresolved regarding the specific outcomes and implications of these calculations.

Contextual Notes

The discussion includes assumptions about the behavior of gases under varying temperatures and pressures, as well as the mathematical complexities involved in solving the van der Waals equation. There are unresolved aspects regarding the selection of appropriate solutions from the cubic equation.

sgstudent
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The pressure exerted on the walls of the container by a real gas is less compared to an ideal gas. This is due to the attractive forces of the gas pulling the molecules back towards the rest of the gas molecules. However, there is also a relationship whereby at lower temperatures, the z is even lesser than at higher temperatures. I am trying to prove that using the van der Waals equation but I am having some trouble with that.

(P+a(n/v)^2 )(V-nb)=nRT

I wanted to compare 2 of the same gases at the same pressure but at different temperature would give us two different volumes. I tried to resolve V from the van der Waals equation but due to the cube on the equation I'm not sure how to evaluate the volume of the 2 gases at different temperatures.

PV/nRT = z = V/V-nb - (an/RTV)

Using the van der Waals equation, the above equation gives us the compressibility factor. I wanted to substitute the volume we obtain from the first equation and temperature to confirm that z is lower at lower temperatures. However because of the problem mentioned I am unable to do so.

Does anyone know how to use the van der Waals equation to explain why at lower temperatures the z is lower?
 
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You could numerically solve the van der Waals cubic equation for V, and if it yields three real solutions you can choose the right one based on an approximate result gotten from a simpler EOS like the Ideal Gas Law. If it yields only one real solution, choosing the right result should be a no-brainer.
 
MexChemE said:
You could numerically solve the van der Waals cubic equation for V, and if it yields three real solutions you can choose the right one based on an approximate result gotten from a simpler EOS like the Ideal Gas Law. If it yields only one real solution, choosing the right result should be a no-brainer.

Would it show that as temperature decreases the compressibility factor falls below 1 more than compared to when a higher temperature is used?
 
sgstudent said:
Would it show that as temperature decreases the compressibility factor falls below 1 more than compared to when a higher temperature is used?
I guess you could obtain several different values of V for different temperatures with the help of a spreadsheet, then calculate each correspondig Z value and plot them against temperature. That'll give you some insight.
 

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