- #1
pb23me
- 207
- 0
Homework Statement
The graphs y=abs(x) and y=(x^2)-6 intersect at x=3 and x= -3What is confusing me is when I set them equal to each other and solve (x^2)-x-6=0 and (x^2)+x-6=0 I get -3,+3,-2,+2
What is the deal with the negative 2 and pos 2?