# Interval bisection

1. Dec 30, 2008

### nokia8650

Is there any general formula for interval bisection, rather than consider two similar triangles each time?

Thanks

2. Dec 30, 2008

### HallsofIvy

Staff Emeritus
I must be misunderstanding what you mean by "interval bisection". The point bisecting the interval from $(x_0,y_0,z_0)$ to $(x_1, y_1, z_1)$, in 3 dimensions, is $((x_0+ x_1)/2, (y_0+ y_1)/2, (z_0+ z_1)/2)$, "averaging" the coordinates. That can be derived by using 'similar triangles' but you surely don't have to rederive it for each application.

3. Dec 30, 2008

### nokia8650

Thanks for the reply. Sorry, I meant linear interpolation, not interval bisection - is there a general formula for this?

Thanks