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Interval bisection

  1. Dec 30, 2008 #1
    Is there any general formula for interval bisection, rather than consider two similar triangles each time?

    Thanks
     
  2. jcsd
  3. Dec 30, 2008 #2

    HallsofIvy

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    I must be misunderstanding what you mean by "interval bisection". The point bisecting the interval from [itex](x_0,y_0,z_0)[/itex] to [itex](x_1, y_1, z_1)[/itex], in 3 dimensions, is [itex]((x_0+ x_1)/2, (y_0+ y_1)/2, (z_0+ z_1)/2)[/itex], "averaging" the coordinates. That can be derived by using 'similar triangles' but you surely don't have to rederive it for each application.
     
  4. Dec 30, 2008 #3
    Thanks for the reply. Sorry, I meant linear interpolation, not interval bisection - is there a general formula for this?

    Thanks
     
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