iVenky said:
Hence, I want to know the intrinsic impedance of an ideal resistor.
The "Intrinsic Impedance" means the resistance that you can put in a transmission (perfectly terminated or infinitely long) line or a medium that will replace the downstream part of the line will have the same effect as the medium. If the resistor is "ideal" then you can replace it with a copy of itself.
I have been trying to think what you actually have a problem with here. The above is a bit glib, I admit but it is the literal answer to your literal question. If you wanted to take that transmission line context into a traveling wave, you are considering the Fields in space or in a waveguide of some kind. You cannot 'connect' any resistor which will perfectly terminate a wave in free space - how would you do that? You would have to connect an antenna of some sort (which would transform any lumped resistor, at its feed point) and which would gather
all the energy that's radiated. Etc. Etc. It doesn't make sense to go too far in that direction so you just have to talk in terms of the
Impedance Of Free Space as the ratio of E and H fields (= about 377Ω and yes "how does the ratio of two fields become a Resistance?" is a fair question. Maths alone can justify that!) and accept that you can't actually replace space with a 'resistor'.
The same thing applies in a Wave-Guiding structure but where, in the waveguide would you place a resistor to produce a perfect termination? All you can do there is to pick off the power with a loop (or something else), placed at a certain point in the guide and feed that signal to a (perfect) Resistor that absorbs all the Power. But the value of the resistor required will depend on where you pick off the signal. Near the wall, the E field is low and the H field is high is the Impedance is Low and , in the middle, the H is low and the E is high so the Impedance is high). You
can tinker with the geometry at the end of
any guide in such a way as to eliminate the reflection from the Load, wherever you couple it but that only means you have transformed the load in such a way as to match it to the Intrinsic Impedance of the guide. The resistor doesn't need to be any particular value (not even purely resistive.
Does that make any sense?