LaTeX Introducing LaTeX Math Typesetting

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Physics Forums has integrated LaTeX mathematical typesetting into its platform, allowing users to create visually appealing mathematical expressions using markup similar to HTML. Users can include LaTeX graphics in posts by wrapping their code in [tex] or [itex] tags for display or inline formatting, respectively. A PDF guide with essential LaTeX commands and symbols is available, along with links to additional resources. The community is encouraged to experiment with the system and share examples, while also being mindful of server load when generating graphics. This addition aims to enhance the clarity and professionalism of mathematical discussions on the forum.
  • #451
a^x_n ...

Edit: You left spaces in your brackets.
 
Last edited by a moderator:
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  • #452
hey how come i can't get it to work ??
 
  • #453
extreme_machinations said:
hey how come i can't get it to work ??
See my edits of your posts.
 
  • #454
\int_{0}^{\frac{\pi}{2}} \log \cos \kappa d \kappa
 
  • #455
Just trying...

\int_{0}^{\frac{\pi}{2}} \log \cos \Omega \ d \Omega

f(x) = \sin x, \mbox{if} \ x \ \epsilon \ (0, \frac{\pi}{2})
 
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  • #456
f(x) = \left {\begin{array}{cc}\sin x,&\mbox{if} \ x \epsilon \ [0, \frac{\pi}{2})\\ \cos x, & \mbox{if} \ x \epsilon \ [\frac{\pi}{2}, \pi)\end {array}\right
 
  • #457
F=GmM_e/r^2
 
  • #458
aaahhaa! now that more like it
hey thanks doc
 
  • #459
f(x)=sinx^2
 
  • #460
int_{0}^{1} sinlogx
 
  • #461
\int_{0}^{1} sin^2logcosx dx
 
  • #462
This is a test

<br /> \begin{array}{1|c|c|c|c|c|}<br /> \text{Fixed Point}&amp;\text{Jacobian}&amp;\text{Eigenvalues}&amp;\text{Eigenvectors}&amp;\text{type}\\<br /> \hline<br /> (0,0)&amp;<br /> \left(\begin{array}{cc}1.5 &amp; 0 \\ 0 &amp; 2 \end{array}\right)&amp;<br /> 2,1.5 &amp;<br /> \left(\begin{array}{ca}0 \\ 1 \end{array}\right)<br /> \left(\begin{array}{ca}1 \\ 0 \end{array}\right)&amp;<br /> \text{Source}\\<br /> \hline<br /> <br /> (0,2)&amp;<br /> \left(\begin{array}{cc}0.5 &amp; 0 \\ -1.5 &amp; -2 \end{array}\right)&amp;<br /> -2,0.5 &amp;<br /> \left(\begin{array}{ca}0 \\ 1 \end{array}\right)<br /> \left(\begin{array}{ca}0.86 \\ -0.51 \end{array}\right)&amp;<br /> \text{Saddle}\\<br /> \hline<br /> <br /> (1.5,0)&amp;<br /> \left(\begin{array}{cc}-1.5 &amp; -0.75 \\ 0 &amp; 0.88 \end{array}\right)&amp;<br /> -1.5,0.88 &amp;<br /> \left(\begin{array}{ca}1 \\ 0 \end{array}\right)<br /> \left(\begin{array}{ca}-0.3 \\ 0.95 \end{array}\right)&amp;<br /> \text{Saddle}\\<br /> \hline<br /> <br /> (4/5,7/5)&amp;<br /> \left(\begin{array}{cc}-0.8 &amp; -0.4 \\ -1.05 &amp; -1.4 \end{array}\right)&amp;<br /> -1.8,-0.38 &amp;<br /> \left(\begin{array}{ca}0.37 \\ 0.93 \end{array}\right)<br /> \left(\begin{array}{ca}0.69 \\ -0.72 \end{array}\right)&amp;<br /> \text{Sink}\\<br /> \hline<br /> <br /> \end{array}<br />

Slick!
 
  • #463
extreme_machinations said:
\int_{0}^{1} sin^2logcosx dx


Doesn't look good.This one does.

\int_{0}^{1} \sin^{2}x \ln\cos x \ dx


Daniel.
 
  • #464
please help, i cannot find the 'does not equal' latex equation
 
  • #466
a \neq b

this should work
 
  • #467
next question, can i download this for my computer, i have a paper due when i return to school, and it will be a vast help to be able to type the symbols.
 
  • #468
Do NOT pay attention to this! (Just the triangle problem)--Do Not pay attention to this!
 
  • #469
Do NOT pay attention to this! (Just the triangle problem)--Do Not pay attention to this!

A\left( t \right) = \frac{{\left\| {\left[ {\vec r_2 \left( t \right) - \vec r_1 \left( t \right)} \right] \times \left[ {\vec r_3 \left( t \right) - \vec r_2 \left( t \right)} \right]} \right\|}}{2}
-----------------
And the coordinate system based on parameter t by unit vectors:

\vec u\left( t \right) = \frac{{\vec r_1 \left( t \right) - \vec r_2 \left( t \right)}}{{\left\| {\vec r_1 \left( t \right) - \vec r_2 \left( t \right)} \right\|}} \\

\vec v\left( t \right) = \frac{{\left[ {\vec r_3 \left( t \right) - \vec r_1 \left( t \right)} \right]\left\| {\vec r_1 \left( t \right) - \vec r_2 \left( t \right)} \right\|^2 - \left[ {\vec r_1 \left( t \right) - \vec r_2 \left( t \right)} \right]\left\{ {\left[ {\vec r_1 \left( t \right) - \vec r_2 \left( t \right)} \right] \cdot \left[ {\vec r_1 \left( t \right) - \vec r_3 \left( t \right)} \right]} \right\}}}{{\left\| {\left[ {\vec r_3 \left( t \right) - \vec r_1 \left( t \right)} \right]\left\| {\vec r_1 \left( t \right) - \vec r_2 \left( t \right)} \right\|^2 - \left[ {\vec r_1 \left( t \right) - \vec r_2 \left( t \right)} \right]\left\{ {\left[ {\vec r_1 \left( t \right) - \vec r_2 \left( t \right)} \right] \cdot \left[ {\vec r_1 \left( t \right) - \vec r_3 \left( t \right)} \right]} \right\}} \right\|}} \\ <br /> \end{array}

Again----Do NOT pay attention to this!
 
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  • #470
Hello everybody

Sorry if this has been discussed already, I couldn't find anything like it:
How can I create a statement like
<br /> \hat{\xi}(g_0) \longrightarrow \infty \ (g_0 \rightarrow g_0^*),<br />
but with the second limit written smaller and below the first arrow?

Thanks, Bruno
 
  • #471
\hat{\xi}\left(g_{0}\right)\substack{\displaystyle{\longrightarrow}\\g_{0}\rightarrow g_{0}^{*}} \infty

Daniel.
 
  • #472
Here's a little modification of dextercioby's suggestion.
\hat{\xi}\left(g_{0}\right) <br /> \underset{ g_{0}\rightarrow g_{0}^{*} <br /> }{<br /> \overrightarrow{\qquad\qquad} <br /> }\<br /> \infty
or
\hat{\xi}\left(g_{0}\right) <br /> \underset{ g_{0}\rightarrow g_{0}^{*} <br /> }{<br /> \overrightarrow{\qquad} <br /> }\<br /> \infty
 
  • #473
Thank you! That's exactly what I've looked for.
 
  • #474
B_z=B_0(1-aZ)
 
  • #475
B_r=B_0br_0
 
  • #476
\int_0^5 f(x) dx = \frac{125}{3}
where f(x) = x^2
 
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  • #477
U can use "{}" or "\qquad" or simply "space \ space" to place a space between "f(x)" and "dx".

Daniel.
 
  • #478
\ln(ab) = \int_1^{a} \frac{1}{t} dt + \int_a^{ab} \frac{1}{t} dt
 
  • #479
s = 1/2(u+v)t
 
  • #480
s = u+v/2*t
 

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