Introducing LaTeX Math Typesetting

[extreme_machinations]

a^x_n ...

Edit: You left spaces in your brackets.

 

[extreme_machinations]

hey how come i can't get it to work ??

 

[Doc Al]

hey how come i can't get it to work ??

See my edits of your posts.

 

[nu_paradigm]

\int_{0}^{\frac{\pi}{2}} \log \cos \kappa d \kappa

 

[nu_paradigm]

Just trying...

\int_{0}^{\frac{\pi}{2}} \log \cos \Omega \ d \Omega

f(x) = \sin x, \mbox{if} \ x \ \epsilon \ (0, \frac{\pi}{2})

 

[nu_paradigm]

f(x) = \left {\begin{array}{cc}\sin x,&\mbox{if} \ x \epsilon \ [0, \frac{\pi}{2})\\ \cos x, & \mbox{if} \ x \epsilon \ [\frac{\pi}{2}, \pi)\end {array}\right

 

[extreme_machinations]

F=GmM_e/r^2

 

[extreme_machinations]

aaahhaa! now that more like it
hey thanks doc

 

[extreme_machinations]

f(x)=sinx^2

 

[extreme_machinations]

int_{0}^{1} sinlogx

 

[extreme_machinations]

\int_{0}^{1} sin^2logcosx dx

 

[saltydog]

This is a test

<br /> \begin{array}{1|c|c|c|c|c|}<br /> \text{Fixed Point}&amp;\text{Jacobian}&amp;\text{Eigenvalues}&amp;\text{Eigenvectors}&amp;\text{type}\\<br /> \hline<br /> (0,0)&amp;<br /> \left(\begin{array}{cc}1.5 &amp; 0 \\ 0 &amp; 2 \end{array}\right)&amp;<br /> 2,1.5 &amp;<br /> \left(\begin{array}{ca}0 \\ 1 \end{array}\right)<br /> \left(\begin{array}{ca}1 \\ 0 \end{array}\right)&amp;<br /> \text{Source}\\<br /> \hline<br /> <br /> (0,2)&amp;<br /> \left(\begin{array}{cc}0.5 &amp; 0 \\ -1.5 &amp; -2 \end{array}\right)&amp;<br /> -2,0.5 &amp;<br /> \left(\begin{array}{ca}0 \\ 1 \end{array}\right)<br /> \left(\begin{array}{ca}0.86 \\ -0.51 \end{array}\right)&amp;<br /> \text{Saddle}\\<br /> \hline<br /> <br /> (1.5,0)&amp;<br /> \left(\begin{array}{cc}-1.5 &amp; -0.75 \\ 0 &amp; 0.88 \end{array}\right)&amp;<br /> -1.5,0.88 &amp;<br /> \left(\begin{array}{ca}1 \\ 0 \end{array}\right)<br /> \left(\begin{array}{ca}-0.3 \\ 0.95 \end{array}\right)&amp;<br /> \text{Saddle}\\<br /> \hline<br /> <br /> (4/5,7/5)&amp;<br /> \left(\begin{array}{cc}-0.8 &amp; -0.4 \\ -1.05 &amp; -1.4 \end{array}\right)&amp;<br /> -1.8,-0.38 &amp;<br /> \left(\begin{array}{ca}0.37 \\ 0.93 \end{array}\right)<br /> \left(\begin{array}{ca}0.69 \\ -0.72 \end{array}\right)&amp;<br /> \text{Sink}\\<br /> \hline<br /> <br /> \end{array}<br />

Slick!

 

[dextercioby]

\int_{0}^{1} sin^2logcosx dx

Doesn't look good.This one does.

\int_{0}^{1} \sin^{2}x \ln\cos x \ dx


Daniel.

 

[lawtonfogle]

please help, i cannot find the 'does not equal' latex equation

 

[dextercioby]

\neq should do it.

Daniel.

 

[lawtonfogle]

a \neq b

this should work

 

[lawtonfogle]

next question, can i download this for my computer, i have a paper due when i return to school, and it will be a vast help to be able to type the symbols.

 

[bomba923]

Do NOT pay attention to this! (Just the triangle problem)--Do Not pay attention to this!

 

[bomba923]

Do NOT pay attention to this! (Just the triangle problem)--Do Not pay attention to this!

A\left( t \right) = \frac{{\left\| {\left[ {\vec r_2 \left( t \right) - \vec r_1 \left( t \right)} \right] \times \left[ {\vec r_3 \left( t \right) - \vec r_2 \left( t \right)} \right]} \right\|}}{2}
-----------------
And the coordinate system based on parameter t by unit vectors:

\vec u\left( t \right) = \frac{{\vec r_1 \left( t \right) - \vec r_2 \left( t \right)}}{{\left\| {\vec r_1 \left( t \right) - \vec r_2 \left( t \right)} \right\|}} \\

\vec v\left( t \right) = \frac{{\left[ {\vec r_3 \left( t \right) - \vec r_1 \left( t \right)} \right]\left\| {\vec r_1 \left( t \right) - \vec r_2 \left( t \right)} \right\|^2 - \left[ {\vec r_1 \left( t \right) - \vec r_2 \left( t \right)} \right]\left\{ {\left[ {\vec r_1 \left( t \right) - \vec r_2 \left( t \right)} \right] \cdot \left[ {\vec r_1 \left( t \right) - \vec r_3 \left( t \right)} \right]} \right\}}}{{\left\| {\left[ {\vec r_3 \left( t \right) - \vec r_1 \left( t \right)} \right]\left\| {\vec r_1 \left( t \right) - \vec r_2 \left( t \right)} \right\|^2 - \left[ {\vec r_1 \left( t \right) - \vec r_2 \left( t \right)} \right]\left\{ {\left[ {\vec r_1 \left( t \right) - \vec r_2 \left( t \right)} \right] \cdot \left[ {\vec r_1 \left( t \right) - \vec r_3 \left( t \right)} \right]} \right\}} \right\|}} \\ <br /> \end{array}

Again----Do NOT pay attention to this!

 

[kuengb]

Hello everybody

Sorry if this has been discussed already, I couldn't find anything like it:
How can I create a statement like
<br /> \hat{\xi}(g_0) \longrightarrow \infty \ (g_0 \rightarrow g_0^*),<br />
but with the second limit written smaller and below the first arrow?

Thanks, Bruno

 

[dextercioby]

\hat{\xi}\left(g_{0}\right)\substack{\displaystyle{\longrightarrow}\\g_{0}\rightarrow g_{0}^{*}} \infty

Daniel.

 

[robphy]

Here's a little modification of dextercioby's suggestion.
\hat{\xi}\left(g_{0}\right) <br /> \underset{ g_{0}\rightarrow g_{0}^{*} <br /> }{<br /> \overrightarrow{\qquad\qquad} <br /> }\<br /> \infty
or
\hat{\xi}\left(g_{0}\right) <br /> \underset{ g_{0}\rightarrow g_{0}^{*} <br /> }{<br /> \overrightarrow{\qquad} <br /> }\<br /> \infty

 

[kuengb]

Thank you! That's exactly what I've looked for.

 

[extreme_machinations]

B_z=B_0(1-aZ)

 

[extreme_machinations]

B_r=B_0br_0

 

[calculus1967]

\int_0^5 f(x) dx = \frac{125}{3}
where f(x) = x^2

 

[dextercioby]

U can use "{}" or "\qquad" or simply "space \ space" to place a space between "f(x)" and "dx".

Daniel.

 

[calculus1967]

\ln(ab) = \int_1^{a} \frac{1}{t} dt + \int_a^{ab} \frac{1}{t} dt

 

[KaneOris]

s = 1/2(u+v)t

 

[KaneOris]

s = u+v/2*t