Inverse Fourier Transform and Power Signals

AI Thread Summary
The discussion revolves around the challenges of finding the inverse Fourier transform of an aperiodic signal given by X(ω) = 2*sin(3(ω-2π))/ω-2π. Key points include the need to apply the frequency shift and scaling properties to manipulate X(ω) into a suitable form for the inverse transform. The relationship sin(τω)/ω is highlighted, along with the use of the sinc function and its inverse Fourier transform. Additionally, participants clarify that for aperiodic signals, the concept of energy should be used instead of power. Understanding these properties and relationships is crucial for successfully completing the problem.
mod31489
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I am having trouble with this homework problem, I know how to get started but I just don't know how to carry through the completion of the problem:

Question: Given the Fourier transform of an aperiodic signal

X(ω) = 2*sin(3(ω-2π))/ω-2π

(a)find its inverse Fourier transform x(t) using only tables and properties
(b) find the power of the signal x(t)


I know that I have to preform Frequency shift property involving the 2π and I have to preform the scaling property for the 3. I also know that I can use the relationship

sin(τω)/ω = τsinc(τω/2)

and the inverse Fourier transform of
τsinc(τω/2) → ∏(t/τ)

The problem I am having is understanding how to perform the frequency shift and the scaling property in order to get X(ω) into the form of sin(τω)/ω so i can preform the inverse Fourier transform. from there the power is equal to x^2(t) which is equal to the

lim T→∞ of ∫ g^2(t)dt from -T/2 to T/2
 
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mod31489 said:
Question: Given the Fourier transform of an aperiodic signal

X(ω) = 2*sin(3(ω-2π))/ω-2π

The problem I am having is understanding how to perform the frequency shift and the scaling property in order to get X(ω) into the form of sin(τω)/ω so i can preform the inverse Fourier transform.

You should look at replacing w with something else so that X(w+?) generates the sin(ax)/x term.

The signal is not periodic so I think you misspoke -- it doesn't make sense to speak about power for aperiodic signals so I think you meant energy. Subtle, I know, but it's important to keep it straight :)
 

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