- #1
Seiya
- 43
- 1
hey lads, i just was wondering if i solved this right:
5. Consider the function f(x) = 3x+cos(x), defined on the interval [0, pi]
(a) prove that f has an inverse function g. Note: you are note expected to find the inverse function g indicate your reasoning.
I dre the graph of f(x) and showed its a one to one function with a horizontal line test... I am not sure this is enough please tell me if i have to do anything extra
then i said that any continuos 1 to 1 function has a inverse function with the change of domain and range...
(b) determine the domain and range of the funcion g
since the function domain was A and range B, the inverse domain is B and range A.
function = d [0,pi] r [1,8.421]
inverse = d[1,8.4] r [0,pi]
(c) determine the derivative g'(3pi/2) Hint: first, show that f(xo) = 3(pi/2) when x0 = pi/2
find the derivative of the function at xo then the derivative of the inverse is 1/derivativefunction
is all my reasoning right? I am sure illl have this on my final, any advice appreciated
5. Consider the function f(x) = 3x+cos(x), defined on the interval [0, pi]
(a) prove that f has an inverse function g. Note: you are note expected to find the inverse function g indicate your reasoning.
I dre the graph of f(x) and showed its a one to one function with a horizontal line test... I am not sure this is enough please tell me if i have to do anything extra
then i said that any continuos 1 to 1 function has a inverse function with the change of domain and range...
(b) determine the domain and range of the funcion g
since the function domain was A and range B, the inverse domain is B and range A.
function = d [0,pi] r [1,8.421]
inverse = d[1,8.4] r [0,pi]
(c) determine the derivative g'(3pi/2) Hint: first, show that f(xo) = 3(pi/2) when x0 = pi/2
find the derivative of the function at xo then the derivative of the inverse is 1/derivativefunction
is all my reasoning right? I am sure illl have this on my final, any advice appreciated