Inverse of A using Cayley-Hamilton?

  • Thread starter Thread starter Rebbeca
  • Start date Start date
  • Tags Tags
    Inverse
Rebbeca
Messages
1
Reaction score
0

Homework Statement


   2 -1 1
A = -1 2 -1
   -1 -1 2
Find A^-1 using Cayley Hamilton Theorem?

Homework Equations


The Attempt at a Solution



http://i.imm.io/lyhB.jpeg I came thus far,

0 = -A^3 + 6A^2 - 11 + 6I

How do I manipulate the above to get A^-1?
 
Last edited by a moderator:
Physics news on Phys.org
Multiply by A^(-1) and simplify?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top