Inverse of method of image charges

AI Thread Summary
The discussion revolves around finding a surface given a set of charges and their image charges, rather than the traditional method of using charges to determine potential surfaces. Participants note that while simple cases can be solved by setting the potential to zero, more complex scenarios may yield multiple surfaces, potentially leading to infinite solutions. The conversation references the "hearing the shape of a drum" problem as a related concept in inverse boundary value problems. It is highlighted that surfaces correspond to areas of constant potential, and every potential value can theoretically produce a valid surface. Ultimately, it is concluded that while unique solutions exist for specific potentials, the exploration of other potential values opens up a broader range of possibilities.
diegzumillo
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Hi all
What if instead of charges and a surface, we were given a set of charges and image charges and have to find the surface, how would you do that?

This is actually part of my homework but I'm pretty sure he doesn't want us to prove it mathematically (the case is obviously a sphere) so I think this forum is more appropriate than homework, as I'd like a more informal discussion on this rather than a direct solution.

I've seen similar problems to this in other fields, like the famous 'hearing the shape of a drum' problem. Inverse of boundary value problems are very interesting, I wonder if this is one of them.

edit: just to get the ball rolling, for simple cases solving \varphi=0 gives you the solution, but more complicated ones could give you several different surfaces (infinite maybe?) and it might be impossible to determine the shape of the surface. This is a guess, of course.
 
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Surfaces are always areas of the same potential. If you have charges and image charges, those surfaces are easy to find. Every surface will work as solution, and every potential value will give one so the set is infinite.
 
mfb said:
Surfaces are always areas of the same potential. If you have charges and image charges, those surfaces are easy to find. Every surface will work as solution, and every potential value will give one so the set is infinite.
Actually, I completely overlooked the fact that the solutions are unique. If you solve for phi=0 that surface is the only solution. Wow, boring.
 
You can solve for phi equal to some other value :).
 
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