Inverse trig substitution integral

  • Thread starter James889
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  • #1
James889
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Hi,

I need to integrate the following:

[tex]\int \frac{x^2}{\sqrt{9-x^2}}[/tex]

So let [tex]x = 3sin\theta[/tex]
[tex]\frac{dx}{d\theta} = 3cos\theta[/tex]

So i now have the integral of [tex]\frac{9sin^2\theta \cdot 3cos\theta}{3cos\theta}[/tex]

How do i go about the integration from here? parts?
 

Answers and Replies

  • #2
vela
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Try simplifying the integrand first.
 

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