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acen_gr

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EDIT:

The problem asks to simplify this: cos(arcsin x)

let arc sin x = θ

EDIT: I have to edit because I received a warning for not posting for #3 and #2. I originally posted "cos(arcsin x)" for #2 because that was what I know that is relevant to the problem. And I apologize for I didn't know it wasn't enough (I'm new here and sorry if I didn't understand the rules well, I thought it was okay to remove the format instructions and just put what is being asked instead. Quoted above is my previous post #3. As I said there, I really don't have any idea and therefore asks for some (can't put any attempt) When I got the hint from the mentors, I was able to work on this:

Let arcsin x = θ

if arcsin x = θ, then x = sinθ

get the cos of θ from given x/1 and should get for cosθ = √1-x

the answer is cos(θ) = √1-x

**1.Homework Statement**The problem asks to simplify this: cos(arcsin x)

## Homework Equations

let arc sin x = θ

## The Attempt at a Solution

Hoping for some explanation. I really don't have any idea. Thank you so much in advance!

EDIT: I have to edit because I received a warning for not posting for #3 and #2. I originally posted "cos(arcsin x)" for #2 because that was what I know that is relevant to the problem. And I apologize for I didn't know it wasn't enough (I'm new here and sorry if I didn't understand the rules well, I thought it was okay to remove the format instructions and just put what is being asked instead. Quoted above is my previous post #3. As I said there, I really don't have any idea and therefore asks for some (can't put any attempt) When I got the hint from the mentors, I was able to work on this:

The problem asks to simplify this: cos(arcsin x)

Let arcsin x = θ

if arcsin x = θ, then x = sinθ

get the cos of θ from given x/1 and should get for cosθ = √1-x

^{2}(by pythagorean theorem)the answer is cos(θ) = √1-x

^{2}
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