Ipho 1987, thermodynamics problem: Moist air ascending over a mountain range

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SUMMARY

The forum discussion centers on the application of the adiabatic equation to moist air ascending over a mountain range, specifically addressing the confusion regarding the heating effect of condensing vapor. Participants clarify that while the air parcel is heated by condensation, it remains adiabatic due to the internal energy changes balancing the expansion work done. The discussion also explores the calculations of equilibrium vapor pressure, mole fractions, and mass fractions of water vapor in moist air, emphasizing the use of the ideal gas law and Dalton's law for approximations. The final results indicate a mass fraction of approximately 6.9 grams of water vapor per kilogram of moist air at M1, with subsequent calculations leading to a consistent temperature prediction at M2.

PREREQUISITES
  • Understanding of the adiabatic process in thermodynamics
  • Familiarity with the ideal gas law and Dalton's law
  • Knowledge of the Clausius-Clapeyron equation
  • Basic principles of thermodynamic properties of moist air
NEXT STEPS
  • Study the derivation and application of the Clausius-Clapeyron equation
  • Learn about numerical methods for solving differential equations in thermodynamics
  • Explore the implications of moisture content on atmospheric thermodynamics
  • Investigate advanced modeling techniques for moist air flow over topography
USEFUL FOR

This discussion is beneficial for atmospheric scientists, meteorologists, and students of thermodynamics who are interested in the behavior of moist air in mountainous regions and the application of thermodynamic principles to real-world scenarios.

  • #61
So now after these corrections the final temperature I get is 270.89K which is about 0.6K higher than without considering ice. And that makes sense since we get some additional energy from freezing water.
 
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  • #62
Jacob White said:
So now after these corrections the final temperature I get is 270.89K which is about 0.6K higher than without considering ice. And that makes sense since we get some additional energy from freezing water.
Very nice Jacob. Using the vapor pressure of ice at the final temperature, what do you now predict for the amount rained per kg?
 
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  • #63
Much more - about 3.737g.
 
  • #64
Jacob White said:
Much more - about 3.737g.
It doesn't seem possible. What vapor pressure did you estimate at the final temperature?
 
  • #65
0.5084 kPa
 
  • #66
Jacob White said:
0.5084 kPa
That sounds right, but it implies 2.32 grams/kg
 
  • #67
Sorry again, I forgot about molar masses. 3.737*18/29=2.32
 
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