Ipho 1987, thermodynamics problem: Moist air ascending over a mountain range

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Homework Help Overview

The discussion revolves around a thermodynamics problem involving moist air ascending over a mountain range, specifically focusing on the application of the adiabatic equation in the context of air that is being heated by condensing vapor. Participants are examining the implications of this heating on the adiabatic process and the assumptions involved.

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants are questioning the validity of using the adiabatic equation when the gas is heated by condensation. There are discussions about the definitions of adiabatic processes and how they apply to the mixture of air and water vapor. Some participants are exploring the implications of approximations made in the problem, particularly regarding temperature changes and the ideal gas law.

Discussion Status

The discussion is active, with participants raising questions about the assumptions in the problem and the appropriateness of the methods used. Some have provided calculations and approximations, while others are seeking clarification on specific points. There is no explicit consensus, but productive dialogue is occurring regarding the underlying principles and calculations.

Contextual Notes

Participants are working within the constraints of a homework assignment, which may limit the depth of exploration into the problem. There are references to specific values and equations that are relevant to the calculations being discussed, as well as a focus on the conditions at specific points in the problem.

  • #61
So now after these corrections the final temperature I get is 270.89K which is about 0.6K higher than without considering ice. And that makes sense since we get some additional energy from freezing water.
 
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  • #62
Jacob White said:
So now after these corrections the final temperature I get is 270.89K which is about 0.6K higher than without considering ice. And that makes sense since we get some additional energy from freezing water.
Very nice Jacob. Using the vapor pressure of ice at the final temperature, what do you now predict for the amount rained per kg?
 
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  • #63
Much more - about 3.737g.
 
  • #64
Jacob White said:
Much more - about 3.737g.
It doesn't seem possible. What vapor pressure did you estimate at the final temperature?
 
  • #65
0.5084 kPa
 
  • #66
Jacob White said:
0.5084 kPa
That sounds right, but it implies 2.32 grams/kg
 
  • #67
Sorry again, I forgot about molar masses. 3.737*18/29=2.32
 
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