Is 1/λ an Eigenvalue of the Inverse of A?

stine23
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How do I prove that if A is an invertible matrix and lambda does not equal zero then one dived by lambda is an eigenvalue of the inverse of A?
 
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First of all, if A is invertible, then none of the eigenvalues can be 0, by definition.

Second, consider

Av = \lambda v

for some eigenvector v. What is

A^{-1}(\lambda v)

?
 
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