MHB Is Absolute Value Necessary for Proving Limit with Epsilon for $\frac{1}{x^4}$?

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The discussion centers on proving that the limit of $\frac{1}{x^4}$ as $x$ approaches 0 is infinity, specifically for a given $M > 0$. The proof involves demonstrating that if $\frac{1}{x^4} > M$, then it follows that $|x| < \frac{1}{M^{1/4}}$. There is a debate about the necessity of using absolute values in this context, with the conclusion that it is important to specify that $x$ is a positive real number. The argument highlights that since it is a two-sided limit, the absolute value consideration is relevant. The discussion emphasizes clarity in the proof's conditions and the implications of the limit.
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Prove that $\lim_{{x}\to{0}}\frac{1}{x^4}=\infty$, given a $M>0$

So we need to prove that $f(x) > M$:

$\frac{1}{x^4}>M$, $\frac{1}{M}>x^4$, $\frac{1}{M^{1/4}}>|x|$

Is that right so far? Is the absolute values necessary in my last statement?
 
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That looks good to me. All you have to do now is to pick up a positive $\delta < 1/M^{1/4}$ such that for all positive real $x < \delta$, $1/x^4 > M$.

Is the absolute values necessary in my last statement?

Well, at least you have to state explicitly that $x$ is a positive real before drawing that argument.
 
I would say yes, because it is a two-sided limit.
 
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