MHB Is Absolute Value Necessary for Proving Limit with Epsilon for $\frac{1}{x^4}$?

  • Thread starter Thread starter Dethrone
  • Start date Start date
  • Tags Tags
    Epsilon Limit
Click For Summary
The discussion centers on proving that the limit of $\frac{1}{x^4}$ as $x$ approaches 0 is infinity, specifically for a given $M > 0$. The proof involves demonstrating that if $\frac{1}{x^4} > M$, then it follows that $|x| < \frac{1}{M^{1/4}}$. There is a debate about the necessity of using absolute values in this context, with the conclusion that it is important to specify that $x$ is a positive real number. The argument highlights that since it is a two-sided limit, the absolute value consideration is relevant. The discussion emphasizes clarity in the proof's conditions and the implications of the limit.
Dethrone
Messages
716
Reaction score
0
Prove that $\lim_{{x}\to{0}}\frac{1}{x^4}=\infty$, given a $M>0$

So we need to prove that $f(x) > M$:

$\frac{1}{x^4}>M$, $\frac{1}{M}>x^4$, $\frac{1}{M^{1/4}}>|x|$

Is that right so far? Is the absolute values necessary in my last statement?
 
Physics news on Phys.org
That looks good to me. All you have to do now is to pick up a positive $\delta < 1/M^{1/4}$ such that for all positive real $x < \delta$, $1/x^4 > M$.

Is the absolute values necessary in my last statement?

Well, at least you have to state explicitly that $x$ is a positive real before drawing that argument.
 
I would say yes, because it is a two-sided limit.