Is anyone here familiar with luminol? (radical reactions)

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The discussion centers on the use of luminol to visualize cavitation through sonochemiluminescence, where ultrasound induces bubble cavitation that generates radicals. The mechanism involves luminol primarily existing as a monoanion, which oxidizes hydroxyl radicals to produce a diazaquinone radical anion. This species reacts with superoxide radicals to form a hydroperoxide addition product, eventually leading to the emission of blue light at 430 nm. A key question raised is whether hydrogen radicals could initiate a similar reaction in place of oxygen radicals. The author expresses interest in exploring luminol's reactions with various oxidants and its potential as a radical detector. The discussion concludes with a note that the initial issues encountered were related to the reaction environment affecting radical production, and a paper on the findings is forthcoming.
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I am currently using luminol to visualise cavitation via sonochemiluminescence. When bubbles in solution are exposed to ultrasound they cavitate and draw vapour inside them. The bubbles crush the vapour breaking bonds and radicals are produced.

These radicals then do the following (from my own work)...

The mechanism can be described as follows; luminol (I) exists predominantly as the monoanion species (II) oxidising the •OH and producing the diazaquinone radical anion (III) [17]. This species react with •O to form a hydroproxide addition product (IV) which through decomposition and relaxation forms the aminophthalate monoanion (V), this deactivates via florescence and emits characteristic blue light at 430 nm [13, 17-20].

My question is, what if there were •H radicals in solution instead of •O radicals, could the same reaction happen?

I have the idea that I could look how luminol reacts with oxidents, or if it is used as a radical detector, but I am unsure of where to start.

Also what would the main differences be between H and O radicals in a physical sense?

Thanks in advance for any thoughts / ideas on this.
 
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Yes, all sorted now, the problem was the environment in which the reactions were taking place that could produce radicals in different numbers. Paper on the way (hopefully!)
 
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