I Is Callen right in claiming dQ=TdS for all quasi-static processes?

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Callen defines a quasi-static process as one that occurs through a dense succession of equilibrium states, suggesting that it traces a continuous curve in the system's configuration space. He asserts that the relationship dQ = TdS, representing heat transfer, is only valid for quasi-static processes, implying that any process not adhering to this equation cannot be considered quasi-static, despite meeting the equilibrium criteria. The discussion raises concerns about the lack of motivation for this conclusion and seeks a general proof to support the claim that dQ = TdS necessarily follows from the definition of quasi-staticity. References to other literature, such as Norton's work on thermodynamic reversibility, highlight ongoing debates about the characterization of quasi-static processes. The inquiry emphasizes the need for clarity and proof regarding the relationship between quasi-static processes and the heat transfer equation.
Anna57
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A question regarding the validity of the relationship $$dQ=TdS$$ for all quasi-static processes. Based on Callen's Thermodynamics.
Hello!

I am currently reading the second edition of Callen's Thermodynamics and an Introduction to Thermostatistics, and I have a question regarding Callen's definition of quasi-static. On page 96, Callen says:

Consider an arbitrary curve drawn on the hypersurface of Fig. 4.3*, from an inital state to a terminal state. Such a curve is known as a quasi-static process. A quasi-static process is thus defined in terms of a dense succession of equilibrium states.

*Fig. 4.3, the hypersurface defined by the entropy function graphed in its configuration space


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Another way of characterizing Callen's definition is that a process is quasi-static if it traces out a continuous curve in the system's configuration space. So far it's all well and good. A little later, Callen claims that the identification of $$TdS$$ as the heat transfer is only valid for a quasi-static process. In seemingly the rest of the book, he takes this to be a necessary criterion for quasi-staticity. A process which does not obey $$dQ=TdS$$, no matter how well it seems to fit the original definition in terms of equilibrium states, is apparently not quasi-static. I am having a lot of trouble understanding how Callen draws this conclusion as it is not motivated and other motivations later on are predicated on this being true. Is it possible to prove, based on the definition of quasi-staticity given above, that it necessarily follows that $$dQ=TdS$$ for any, arbitrary quasi-static process? I have searched far and wide but cannot find any general proof. I am having trouble believing it is even true, and sources online even seem to disagree.
 
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The following publication might be of help for you:

The impossible process: thermodynamic reversibility’ by John D. Norton (Studies in History and Philosophy of Science Part B: Studies in History and Philosophy of Modern Physics, 55, pp. 43–61)

Abstract
Standard descriptions of thermodynamically reversible processes attribute contradictory properties to them: they are in equilibrium yet still change their state. Or they are comprised of non-equilibrium states that are so close to equilibrium that the difference does not matter. One cannot have states that both change and no not change at the same time. In place of this internally contradictory characterization, the term “thermodynamically reversible process” is here construed as a label for a set of real processes of change involving only non-equilibrium states. The properties usually attributed to a thermodynamically reversible process are recovered as the limiting properties of this set. No single process, that is, no system undergoing change, equilibrium or otherwise, carries those limiting properties. The paper concludes with an historical survey of characterizations of thermodynamically reversible processes and a critical analysis of their shortcomings.
 
Anna57 said:
Is it possible to prove, based on the definition of quasi-staticity given above, that it necessarily follows that $$dQ=TdS$$ for any, arbitrary quasi-static process? I have searched far and wide but cannot find any general proof. I am having trouble believing it is even true, and sources online even seem to disagree.
It appears to me that Callen’s deduction of ##dQ = T dS## for quasi-static processes is essentially contained in sections 1.8 and 2.1.

Section 1.8 defines ##dQ## for a quasi-static process. Section 2.1 derives ##dQ = T dS## for quasi-static processes.

Maybe I'm overlooking something.
 
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