Is Euclidean space an affine space?

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SUMMARY

Euclidean space is often discussed in the context of both linear vector spaces and affine spaces. The distinction lies in the ability to perform translations without altering the system's properties. While translations in the context of a Lagrangian, such as ##L = 1/2 \ m v^2 + mgy##, do not affect the physics, they raise questions about translational invariance as described in Noether's theorem. This discussion clarifies that the terminology used in physics may differ from mathematical definitions, leading to potential confusion regarding the classification of Euclidean space.

PREREQUISITES
  • Understanding of Euclidean space and its properties
  • Familiarity with linear vector spaces and affine spaces
  • Basic knowledge of Lagrangian mechanics
  • Awareness of Noether's theorem and its implications
NEXT STEPS
  • Explore the mathematical definitions of affine spaces versus linear vector spaces
  • Study Lagrangian mechanics in detail, focusing on the role of translational invariance
  • Investigate Noether's theorem and its applications in physics
  • Examine examples of physical systems where translational invariance plays a critical role
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Students and professionals in mathematics and physics, particularly those interested in theoretical mechanics and the foundations of space concepts.

BruceW
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Hi everyone,

I have a question that I'm not sure about. I wanted to know if it is standard to think of Euclidean space as a linear vector space, or a (more general) affine space? In some places, I see Euclidean space referred to as an affine space, meaning that the mathematical definition of the space allows us to make translations without affecting our system.

But on the other hand, if we have a Lagrangian like ##1/2 \ m v^2+mgy## then a translation ##y \rightarrow y+d## changes the Lagrangian to ##L \rightarrow L+mgd##. Now, I know that this does not affect the physics of the system, since it does not matter if we add a constant to the Lagrangian. But when people talk about Noether's theorem, they say that due to the form of this Lagrangian, we do not have 'translational invariance'. So are they including the Lagrangian as a physical observable of the system?? And so, is our space a linear vector space, not an affine space? Maybe they are using the term 'translational invariance' to mean something different to the 'translational invariance' that allows us to call our space affine? (and if so, then that is pretty darn confusing).

thanks in advance :)
 

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