Is freezing point always depressed by a solute?

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    Freezing Point
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The freezing point is generally depressed by a solute due to the disruption of the solid lattice structure, making it harder for the solution to solidify. Stronger solute-solvent interactions can enhance this effect by increasing disorder in the solution. In the case of amorphous solids, the lack of a defined structure complicates the influence of solutes, as they may not interfere with a solid structure in the same way. Amorphous solids do not have a distinct freezing point and do not undergo phase changes at a constant temperature. The concept of vitrification is relevant in understanding the behavior of amorphous solids.
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Homework Statement


Is the freezing point always depressed by a solute even if solute-solvent interactions are stronger than solute-solute and solvent-solvent interaction? What about amorphous solids?

2. Relevant knowledge
According to my chemistry teacher's powerpoints, the freezing point is always depressed by the presence of a solute because the solute particles disrupt the lattice structure of the solid.

The Attempt at a Solution


Thus, the solution remains liquid at lower than normal temperatures due to the added difficulty of forming the solid structure. The stronger solute-solvent interactions add to this disorder.

In amorphous solids where there is little/no organized set structure to speak of, I don't know how solute particles would interfere unless the solute forms its own competing structure as a solid. Otherwise, I'm in the dark.
 
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Amorphous solids don't have a freezing point.
 
Do amorphous solids not have changes of state?
 
Not at a constant temperature. Google vitrification.
 
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