Is Internal Energy Always Constant in Thermodynamic Systems?

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Discussion Overview

The discussion revolves around the constancy of internal energy in thermodynamic systems, exploring concepts related to work, heat transfer, and adiabatic processes. Participants examine the implications of different conventions in thermodynamics and the conditions under which internal energy may change.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Conceptual clarification

Main Points Raised

  • One participant questions whether internal energy is always constant, suggesting that work done on the system might require heat absorption to maintain constant internal energy.
  • Another participant argues that in an adiabatic process, internal energy will not remain constant as compressing the system increases internal energy and temperature.
  • There is a discussion about the conventions used in thermodynamics, with one participant expressing confusion over the signs in the equations for internal energy and work.
  • A participant explains that adiabatic processes can be reversible if they occur in a controlled manner, not necessarily in a single large step, and that real processes are often neither completely adiabatic nor reversible.
  • Clarification is provided regarding the conventions in physics versus chemistry, noting that the definitions of work and energy changes can differ between disciplines.

Areas of Agreement / Disagreement

Participants express differing views on the relationship between work, heat transfer, and internal energy, indicating that there is no consensus on whether internal energy remains constant under all conditions. The discussion reflects multiple competing interpretations of thermodynamic principles.

Contextual Notes

Participants acknowledge the complexity of thermodynamics compared to mechanics, highlighting that the assumptions and definitions can significantly affect the understanding of internal energy changes.

Who May Find This Useful

This discussion may be of interest to students and practitioners in physics, chemistry, and engineering who are grappling with the concepts of thermodynamics and the implications of different conventions in the field.

Inertigratus
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So, is the internal energy of a system always constant?
I mean, if work done on the system is negative by convention.
dU = dQ - pdV
Then if work is done on the system, does that mean that it has to absorb heat to keep the internal energy constant? and if the system does work, it has to release heat?
 
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If the system is adiabatic it won't be able to release, absorb heat, and then the internal energy will not be constant. That is, if you compress(give work) to an adiabatic system it will increase U and it will get hotter.
And I think you got it backwards, if the system does work it needs to absorb heat to maintain U and if it receives work it must release heat.
 
Right, actually I think the convention confuses me a little. If the system does work, would that change the minus into a plus (since it's positive)?
Or is it, dU = dQ - (-pdV) if work is done on the system, and dU = dQ - pdV if the system does work?
Another small question, how can an adiabatic process be reversible (isentropic)?
I mean, for a process to be reversible it has to happen in infinitely small steps, so that the system enters thermodynamic equillibrium in each step, right?
But for an adiabatic process, it happens in one big jump, so how can it be reversible?
 
I'm not a thermo master or anything but let's see
You don't need to do it in one big jump, yes when you do it fast it's adiabatic because there will be no time to exchange heat with the surroundings but if you use an insulating container you will also not exchange heat and it will be adiabatic, in an ideal situation of course.
Real processes are neither completely adiabatic nor reversible.



About the convention, in physics it's normally dW= PdV, without the minus.
And dU= dQ - dW
So when the system does work on the surrounding,expands , that is final volume is bigger than initial volume, the integral is positive. W is positive.
So -dW is negative, the system loses internal energy.

In chemistry, physical chemistry, chemical engineering...it's backwards.
Yes, it's confusing, hope I explained it right.
 
Oh right, so isentropic processes ideally occur only in isolated systems then?
I understand now, not used to the thinking in thermo yet.
Thanks!
 
Thermo is kinda complex, since it's not based on simple laws like mechanics that work on every situation
 

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