Is it possible to find the SD without the data?

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To find the standard deviation (SD) when given the mean and a specific percentile value, knowing the distribution shape is crucial; in this case, it is normal. The SD can be calculated using the formula σ = (value at 99th percentile - mean) / a, where a is approximately 2.33 for the 99th percentile. Using this method, the calculated SD is about 0.36. Consequently, the estimated value at the 90th percentile is approximately 4.26. This approach provides a reasonable estimate based on the normal distribution.
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I have the mean and I have the value at a percentile (99th percentile to be specific). I am just wondering if it's possible to find the SD. Actually, what I am trying to find is the value at the 90th percentile (I think I need the SD to do it, but maybe just maybe there's another method...)


Just in case, the mean is 3.8 and the value at the 99th percentile is 4.64
 
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You need to know the shape of the distribution. If it is normal you can get the S.D. (σ)from the data given by looking up the value for a when aσ = .99. I get a ≈ 2.33, but I suggest you check it. σ = (4.64 - 3.8)/2.33.
 
Oh yeah, I forgot to say it's a normal distribution. I used the invNorm function to see which standard deviation best models the situation, so I found out that 0.36 does it pretty well. So the value I got for the 90th percentile is more of an estimate (4.26), but I think it fits well enough.
 
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