I have the following parallel RC circuit. At time T = 0, the switch will close and the circuit will be connected. We assume that prior to T = 0, the circuit was at a steady-state.
I want to calculate VL(t) -- but I am being told that this is not possible for this problem, and would only be possible if there was an additional resistor or inductor (located where the switch is right now).
The professor and other individual who have told me this say that without this additional inductor / resistor, it is not possible to calculate VL(t) as the resistor will be shorted. This makes sense at T = 0, when the inductor will act as a short circuit, and the resistor will in-effect be shorted (as VL(0) = 0).. However, as T increases, the inductor will charge, and the voltage across the inductor will increase, until it acts as an open circuit and all current flows through R.
Therefore, I do not understand why it is not possible to solve for VL(t).
Can anyone provide clarification? I think this might just be miscommunication.