Is $\lim_{\Delta x \to 0}f(x+\Delta x) \cdot \Delta x = 0$ True?

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  • Thread starter Thread starter gabel
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Discussion Overview

The discussion centers around the limit expression lim_{Δx → 0} f(x + Δx) · Δx and whether it equals zero. Participants explore conditions under which this limit may hold true, including considerations of continuity and boundedness of the function f.

Discussion Character

  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants assert that the limit is not always true, but holds if f is continuous at x or if lim_{Δx → 0} f(x + Δx) exists.
  • It is suggested that if f is bounded near x, the limit can be shown to equal zero using the Squeeze Theorem.
  • Concerns are raised regarding cases where f is unbounded near x, leading to the possibility that the limit may not exist or may not equal zero.
  • One participant expresses a need to demonstrate that lim_{Δx → 0} f(x_0 + Δx) · Δx = k for some constant k, seeking further conditions on f.
  • Another participant questions the meaning of "possible" in this context, reiterating that it is not true in general.
  • There is a mention of specific functions, such as f(x) = 1/x, to illustrate cases where the limit does not equal zero.

Areas of Agreement / Disagreement

Participants generally agree that the limit does not hold true in all cases, with multiple competing views on the conditions under which it may or may not equal zero. The discussion remains unresolved regarding specific functions that may contradict the general statement.

Contextual Notes

Limitations include the dependence on the continuity and boundedness of the function f, as well as the specific behavior of f near the point of interest. The discussion does not resolve the implications of these conditions.

gabel
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Is the following true, if no is there som theory i can studdy?

##\lim_{\Delta x \to 0}f(x+\Delta x) \cdot \Delta x = 0##
 
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gabel said:
Is the following true, if no is there som theory i can studdy?

##\lim_{\Delta x \to 0}f(x+\Delta x) \cdot \Delta x = 0##

This is not always true. It is true if ##f## is continuous at ##x## or if the ##\lim_{\Delta x \to 0}f(x+\Delta x) ## exists; use the product law for limits. It is true if ##f## is bounded near ##x##; use the Squeeze Theorem.

If ##f## is unbounded near ##x##, the the limit may exist but not be ##0##, or it just might fail to exist. Look at ##f(x)=1/x## and ##f(x)=1/x^2## with ##x=0##.
 
Thanks, but i really need to show the following if its possibole.

## \lim_{\Delta x \to 0} f(x_0 + \Delta x) \cdot \Delta x= k ## Where k, is a constant.

Is there something i can say aboute f?
 
What do you mean by "possible"? You have already been told that it is NOT true in general. You have also been told that if f is continuous at x_0 or if \lim_{\Delta x\to 0} f(x+ \Delta x) exits then it is true.
 
I was told in general, so there must be som functions that does the oppeist?
 
gabel said:
I was told in general, so there must be some functions that does the oppeist?
Who told you that? gopher_p, in the only other response here, said "this is not always true".

Take f(x)= 1/x, x_0= 0.
 

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