- #1
bugatti79
- 794
- 1
I calculate
1) ##\Omega=
\begin{bmatrix}
1 & 3 &1 \\
0 & 2 &0 \\
0& 1 & 4
\end{bmatrix}## as not Hermtian since ##\Omega\ne\Omega^{\dagger}## where##\Omega^{\dagger}=(\Omega^T)^*##
2) ##\Omega\Omega^{T}\ne I## implies eigenvectors are not orthogonal.
Is this correct?
1) ##\Omega=
\begin{bmatrix}
1 & 3 &1 \\
0 & 2 &0 \\
0& 1 & 4
\end{bmatrix}## as not Hermtian since ##\Omega\ne\Omega^{\dagger}## where##\Omega^{\dagger}=(\Omega^T)^*##
2) ##\Omega\Omega^{T}\ne I## implies eigenvectors are not orthogonal.
Is this correct?