Is My Calculation for Film Thickness Using Interference Method Accurate?

tan-X1
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After I read many articles about measuring film thickness by interference method.

I tried to calculate flow that papers but I can't

the equation is

d= (y1*y2)/(2*(n1y2-n2y1))

for an easy I approximate n1 =n2

so

d= (y1*y2)/(2*n(y2-y1))


y1 = 350 nm
y2 = 380 nm
n = 2.35

I want to find out "d"

it seems to be easy

but I always get d = 944 nm

unfortunately, it's wrong

d have to be 472

that means I forgot to divide 2 in this eq.

however, the eq use to be right.

I don't know what's wrong in my calculation.
 
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Ahh, I am wondering

I track this eq from original eq

2nd=my1

2nd=(m+1/2)y2

I am able to get

d=(y2*y1)/(4*n*(y2-y1))

from this eq. I can get the right answer

so, what's wrong in this eq.

d= (y1*y2)/(2*n(y2-y1))

?
 
Please do NOT post the same question in more than one forum.
 
tan-X1 said:
the equation is

d= (y1*y2)/(2*(n1y2-n2y1))

for an easy I approximate n1 =n2

so

d= (y1*y2)/(2*n(y2-y1))
Why don't you explain what this equation represents and define the terms? What are n1 and n2? y1 and y2?
 
Sorry mate.

Now, I've already known.

Thank you.
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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