Is My Calculus Derivation Correct?

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SUMMARY

The forum discussion centers on the correctness of a calculus derivation related to finding the first derivative of a function. The user expresses uncertainty about their final answer, specifically questioning the equality of the expressions \(\frac {dy} {dx} = \frac {1} {2} ( \frac {1} {x+1} - \frac {1} {x-1} )\) and \(\frac {1} {2x+1} - \frac {1} {2x-1}\). Other participants confirm that the user's derivation contains a careless error in simplification, particularly in the terms involving \(2(x+1)\) and \(2(x-1)\).

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Jason03
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My work is posted below...the problem seems pretty straight forward...but I am I don't think IM getting the correct answer...

any suggestions?

http://img221.imageshack.us/img221/742/calcek4.jpg

(finding first derivative)
 
Last edited by a moderator:
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Jason03 said:
My work is posted below...the problem seems pretty straight forward...but I am I don't think IM getting the correct answer...

any suggestions?

http://img221.imageshack.us/img221/742/calcek4.jpg

(finding first derivative)

I think everything looks fine up until the last equality:

[tex] \frac {dy} {dx} = \frac {1} {2} ( \frac {1} {x+1} - \frac {1} {x-1} )[/tex]

but

[tex] \frac {1} {2} ( \frac {1} {x+1} - \frac {1} {x-1} ) \neq \frac {1} {2x+1} - \frac {1} {2x-1}[/tex]
 
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yeap hitman is right.

Careless error?

2(x+1) = 2x+2
and same goes for the next one.
 

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