No, it is not! Actually it is something to do with the scalar wave equation. Let us assume that a solution of the scalar wave equation ( Ω ) is a steady state with amplitude ψ and the oscillating factor exp(-tω), Ω=ψ(r)exp(-itω(r)). Usually the frequency ω assumed to be a constant. Now, suppose it depends of coordinates: ω(r). The kinetic energy, velocity, and De-Broglie frequency (f=cmv/h) of the electron that is orbiting the atom will depend of radius. We can express De-Broglie's frequency of the electron through its kinetic energy. Now we can request that the local frequency of the Ω be equal to De-Broglie's frequency of the electron at the same location: ω(r)=f. Substituting Ω to the wave equation we will find the equation for ψ which will be exactly the Schrodinger Equation. That means that ψ-function of Quantum Theory is actually the amplitude of a standing wave of some scalar wave equation!