Is RMS speed dependent on pressure?

Click For Summary
SUMMARY

The root mean square (r.m.s) speed of gas molecules is solely dependent on temperature, not pressure, as established by the kinetic theory of gases. Increasing the pressure of a gas without changing its volume requires work to be done on the gas, which can lead to an increase in temperature and, consequently, an increase in r.m.s speed. The discussion emphasizes that while pressure affects the motion of gas particles, it does not directly alter the r.m.s speed if temperature remains constant. The first law of thermodynamics is applied to explain the relationship between internal energy, heat flow, and work done on the gas.

PREREQUISITES
  • Understanding of the kinetic theory of gases
  • Familiarity with the first law of thermodynamics
  • Knowledge of root mean square speed calculations
  • Basic concepts of pressure, volume, and temperature relationships
NEXT STEPS
  • Study the kinetic theory of gases in detail
  • Explore the implications of the first law of thermodynamics on gas behavior
  • Learn about adiabatic processes and their effects on gas properties
  • Investigate the relationship between temperature and molecular kinetic energy
USEFUL FOR

Students of physics, particularly those studying thermodynamics and gas laws, as well as educators and professionals seeking to deepen their understanding of molecular motion and energy relationships in gases.

phymath7
Messages
48
Reaction score
4
TL;DR
One question appeared in my test.It asked that if pressure of two gases are increased to two times of the previous,then how much change would happen to the ratio of the r.m.s speed of the two gases keeping the temperature constant?
As it is clear from the formula for r.m.s speed ,it is only dependent of temperture for a particular gas,I think the answer should be "No change happens".But I wonder whether there is more insight to this.And is my assumption true?
 
Science news on Phys.org
phymath7 said:
TL;DR Summary: One question appeared in my test.It asked that if pressure of two gases are increased to two times of the previous,then how much change would happen to the ratio of the r.m.s speed of the two gases keeping the temperature constant?

As it is clear from the formula for r.m.s speed ,it is only dependent of temperture for a particular gas,I think the answer should be "No change happens".But I wonder whether there is more insight to this.And is my assumption true?
You are correct.

I think that the insight is that one could think adding pressure will affect the motion of the gas particles, and hence their speed. (A higher pressure will affect the motion in some way. Can you see what it is?)
 
DrClaude said:
You are correct.

I think that the insight is that one could think adding pressure will affect the motion of the gas particles, and hence their speed. (A higher pressure will affect the motion in some way. Can you see what it is?)
So you are saying that a higher pressure will somehow affect the r.m.s speed?But I don't see how it happens right now.
 
phymath7 said:
So you are saying that a higher pressure will somehow affect the r.m.s speed?But I don't see how it happens right now.
If temperature is not forced to remain constant then consider how you go about increasing the pressure of the gas. Do you, for instance, force a piston further into a cylinder?
 
phymath7 said:
So you are saying that a higher pressure will somehow affect the r.m.s speed?But I don't see how it happens right now.
No, it doesn't affect r.m.s. speed, as you noted yourself. But it does affect something else related to the motion of the molecules.
 
phymath7 said:
So you are saying that a higher pressure will somehow affect the r.m.s speed?But I don't see how it happens right now.
Just apply the first law: ##\Delta U = Q+W## where W is the work done on the gas and Q is the heat flow into the gas.

A higher pressure without a change in volume (W=0) can only be achieved by increasing temperature (##\Delta U>0##) by positive heat flow (Q>0). Higher T means higher molecular rms speed (higher average molecular translational KE).

A higher pressure with compression requires positive work to be done on the gas (W>0). So if it is done adiabatically (Q=0) ##\Delta U>0## which results in higher molecular rms speed.

The only way to increase pressure without increasing molecular rms speed (##\Delta U \le 0##) is to compress with ##Q+W\le 0## (ie. heat flow out of the gas is greater than or equal to the work done on the gas).

AM
 
Last edited:

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 16 ·
Replies
16
Views
6K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
14
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K