First compute the energy lost to space = emissivity * Stef Boltz * Temp difference
This assumes a thermos with a opening of 1cm radius. Water has an emissivity of .99. and that the water is already a 0, so actually the losses will be higher, since it starts at say 20C.
Here are the numbers I used.
Stef.Boltz 5.7 E-8 \frac J {(m^2 s K^4)}
emissivity 0.99
radius 0.01 m
Area 3.14 E-4 m^2
Twater 273K
Tspace 3K
Tdiff 287K
Tdiff^4 5.314E+09 K^4
Heat loss/s 9.42E-02 J/s
hr 8
sec 29280
2.759E+03 J heat loss over 8hr
Now compute how much energy per g to freeze water.
heat of fusion 334 J/g
4.186J
Water temp 20C
m(ct+h) 4 417.72 J/g
conclusion:
If you could point your bottle at a sufficiently dark part of the sky you should be able to freeze about 4 or maybe 5g of water. I have left some room for environmental losses. Since you want to keep it pointed at a dark place you will need a clock drive, different problem.
The more light that enters the bottle the higher the temperature you are radiating to thus the lower your losses. If the moon was within view from the bottom of the bottle you certainly would not freeze the water.
It has been a long time since I have done this sort of calculation, hope I got it all right. Note that the opening radius was just pulled out of the air, seems like a reasonable value, if it gets to big then the environmental loss will increase, smaller you lose less energy.
1) Is space enough of an insulator where convection is not an issue?
For the third time neither convection nor conduction are present in space.
2) Would a mostly-white spacecraft radiate more energy than it would receive from the Sun?
Color is not what determines whether a object adsorbs or emits energy. All that matters is the temperature of the object. If a surface of the object can see the sun, as long as it is at a lower temperature then the sun it will adsorb energy. If a surface of the object can see deep space it will lose energy if its temperature is above 3k. If it can see the Earth it will either loss or gain depending on whether it is colder or warmer then the Earth's surface temperature. This is why satellites are rotating, to ensure that one side does not overheat while the other freezes.