Is Stair Climbing Acceleration Dependent on Distance and Time Squared?

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The discussion centers on the relationship between acceleration, distance, and time in the context of stair climbing. The equation a = d/t^2 is questioned, with clarification that for uniform acceleration from rest, the correct formula is a = 2d/T^2. It is noted that most individuals do not climb stairs with increasing speed, which affects the applicability of these equations. Additionally, gravity is acknowledged as a force acting on the climber but is not directly involved in the acceleration calculation for stair climbing. The conversation emphasizes the complexity of motion and the need for accurate formulas in physics.
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a= d/t^2. Therefore is it the case that the acceleration involved in stair climbing is the distance of the slope divided by the time^2? Where does gravity fit into it?
 
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p75213 said:
a= d/t^2.
Where did you get that relationship? For uniform acceleration starting from rest, the acceleration would be: 2d/T^2.

In general, a ≡ Δv/Δt.
Therefore is it the case that the acceleration involved in stair climbing is the distance of the slope divided by the time^2?
No. Most folks don't climb stairs with increasing speed.
Where does gravity fit into it?
It doesn't. Gravity is just one of the forces acting on the stair climber.
 

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