Is the Angle of a Projectile at 1/4 of its Flight the Same as When it is Fired?

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SUMMARY

The discussion centers on the analysis of a projectile's trajectory, specifically the angle at one-fourth of its flight compared to the launch angle. It is established that the angle of the projectile at 1/4 of its flight is not the same as the launch angle. The slope of the tangent line at any point on the projectile's path corresponds to the velocity vector's direction at that point, which changes throughout the flight. The participants emphasize the importance of distinguishing between initial and subsequent angles, as well as the horizontal and vertical components of velocity.

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  • #31
jeff12 said:
Okay, so then am I suppose to find the launch angle first and then find the angle at another time after?
No, you have no way to find out the launch angle. It is one of the inputs to the question. Just leave it as an unknown, ##\theta_0##. Rewrite your equation in post #28 using ##\theta_0## and ##v_0## as appropriate... then you are done.

@jeff12, I'm glad you liked my post, but please bring this thread to a satisfactory conclusion by posting that equation using ##\theta_0## and ##v_0## as appropriate.
 
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  • #32
The best way to think about it is to use these ideas:

1. The vertical component of the velocity ##v_y## will be half of its original value. (Can you explain why?)

2. The horizontal component of the velocity ##v_x## stays the same.

3. ##\displaystyle \tan \theta=\frac{v_y}{v_x}##.
 
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