I'm going to work through some exercises that will help with this problem. I really working on things geometrically, but I'm probably biased because I didn't feel I understood what was going on until I really understood these space-time diagrams.
If my directions aren't clear, I can try drawing these diagrams and attaching the image.
Exercise 1: synchronization of clocks
Here is a method of geometrically synchronizing clocks. This is theoretically important because it demonstrates that you can do such a thing with absolutely no notion of a reference frame. (And we will use it to prove a theorem!)
First off, we have to figure out how to draw space-time. Take out a sheet of paper. Let's decide that time runs vertically and space runs horizontally, and that light-like lines are at 45° angles.
Now, let's say we have a clock traveling inertially. Represent this by drawing a line on your paper. Since anything travels in a time-like direction, this means the line will be closer to vertical than horizontal.
Now draw a line parallel to the first line. This could be another clock that is "stationary" with respect to the first one.
Now, we synchronize clock synchronization!
Pick a point A on the first line. Draw the two light-like lines passing through A. These will both intersect the second line, let's label those points B and C.
(Physically, it means we send a light flash from point B that is received and reflected at point A, and received at point C... or swap B and C if you labelled them the other way)
Let D be the midpoint of B and C.
We synchronize the clocks by specifying that the times at points A and D are equal. We can call the line AD a
line of simuntaneity.
(Take a moment to convince yourself this gives the "right" result when the clocks are "stationary")
Theorem: The angle bisector of angle <ADB is light-like. Similarly for <ADC.
A tricky theorem. It has lots of useful corollaries.
Corollary: If two clocks are synchronized by the above method, and their worldlines are at a (Euclidean) angle of x° from vertical, then the line of simultaneity are at an angle of (90-x)° from vertical.
Corollary: You only need one clock to determine the lines of simultaneity.
Corollary: Multiple clocks on parallel worldlines may be simultaneously synchronized by the above method.
These set the foundation of the notion of an
inertial reference frame. Also, it gives a quicker geometric way of synchronizing two clocks traveling parallel worldlines: you can simply draw a line of simultaneity wherever you need to do so.
Exercise 2: time dilation
Now that we know how to draw lines of simultaneity, we can work through one of the classical experiments. We're going to have to use the metric this time.
We have two spaceships, each with a clock on its front and rear. The clocks on each ship are synchronized by the above method.
Let's assume, for simplicity, that one of the spaceships is traveling vertically. Draw two vertical lines denoting that ships clocks.
Draw a single slanted line denoting one of the clocks on the other ship. This intersects the two vertical lines in points A and B.
Let the coordinates of point A be (x, t), and of point B be (x', t'). (We don't need their exact values)
Now, since the lines of simultaneity for the vertical clocks are horizontal, we can compute a time difference of |t - t'|.
Using the metric, I can compute the proper time along the line segment AB, which is √( (t-t')² - (x - x')² ), which is clearly less than |t - t'|. Thus, we've geometrically determined time dilation.
Notice, in particular, that this experiment requires
three clocks. We can reduce the number to two, by using the (here, horizontal) lines of simultaneity instead of the other vertical clock, allowing us to define the rate of the other clock with respect to the
coordinate time defined by the lines of simultaneity.
In fact, we don't need the first clock at all -- we can simply specify some parallel space-like lines as being the lines of simultaneity of some reference frame, and then observe the rate of a particular clock with respect to this coordinate time.
(Again, emphasizing that time dilation is a clock vs coordinate time, not one clock vs another clock)
The answer to your question is yes: in this circumstances, in the reference frame defined by the clocks of one ship, the clocks of the other ship will be observed to be dilated, and vice versa.
one of them had done all the traveling (big circle at constant velocity to Altair and back) while one remained at rest
That's impossible: I think you meant constant
speed. Constant velocity would mean it was traveling in a straight line through space-time. Then, we have the initial and final points lying on
both (straight) worldlines, and thus they must be the same line.
Anyways, one of these lines will be straight, and one will be a curve (some sort of helix-like thing in 3D space-time). There's a theorem that the
longest time between any two time-like separated points is a straight line. (Analogous to the shortest distance between two space-like separated points is a straight line)
... how does one know the difference between the two circumstances when encountering a passing spaceship?
I'm not sure exactly what you mean...
Anyways, let's observe what acceleration does to lines of simultaneity, since we can do that now! (I'm not sure this relates to your question or not, but it's still a good exercise!)
Let's draw a worldline of a clock that accelerates. Start off by drawing a vertical line from the bottom of your paper. (I'm assuming forward in time runs upward). Then, gently arc clockwise a short distance, then draw it the rest of the way as straight (but now slanted). Put a little point where it started and finished arcing, and we'll call the time at those points 1 and 2. Mark two other points on the world line corresponding to times 0 and 3.
(So, it went straight from 0 to 1, arced from 1 to 2, then straight from 2 to 3)
Draw the lines of simultaneity at points 0 and 1: they should be horizontal. These lines correspond to coordinate times 0 and 1.
Do the same at points 2 and 3: the lines should be slightly counterclockwise of horizontal. These correspond to coordinate times 2 and 3.
Notice that way off to the left of the diagram, you have the
same point being marked as both coordinate time 0 and coordinate time 2! Yuck! And off to the right, you can see a larger gap than "normal" between coordinate times 1 and 2! This is the yuckiness that is acceleration.
If you want, try to fill in lines of simultaneity corresponding to some times between 1 and 2, and see if you can "watch" the lines rotating as you progress along the worldline.
Really, one ought only to work with coordinates in an "infintiessimal" neighborhood of an accelerating particle, to avoid this weirdness. The only reason we get nice, global coordinates in the inertial case is because our space is so nice. When we progress to General Relativity, we don't get any niceness, so in
all cases, lines of simultaneity only define coordinates in an "infinitessimal" neighborhood.