Is the Magnitude of Proton's Acceleration Constant?

AI Thread Summary
The discussion centers on the acceleration of a proton defined by the equation a = CvxB, where a, v, and B are vectors and C is a constant. It is established that if the velocity v is constant, then the acceleration a must be zero. The relationship between acceleration and velocity is explored through their scalar product, which indicates that acceleration is perpendicular to velocity, resulting in no work being done. The conclusion reached is that while the direction of velocity changes, its magnitude remains constant, leading to unchanged kinetic energy. The problem is ultimately resolved by confirming that the magnitude of both velocity and acceleration is constant.
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A proton has the acceleration a=CvxB, where a is the cross product of v and B (a,v,B are vectors). C is a constant and the magnetic field is constant. Prove that the magnitude of the v and a are constant.

I know I have to somehow prove the derivative of a or v to be zero, but i have no idea how to start. i know if v is constant, then a must be 0.

a=CvxB
(da/dt)=C(dv/dt)xB

i also wrote down |a|=|Cv||B|sintheta, but that doesn't help at all.
 
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If the acceleration is the vector product of the velocity and something else, the acceleration is at right angles to the velocity. The scalar product of acceleration and velocity must then be zero. (The scalar product of two vectors is the product of their magnitudes and the cosine of the angle between them. Cosine of 90 degrees is zero.) But this scalar product is the power per kilogram (work per kilogram per second) delivered by the force.

The derivative to time of the velocity is not zero; it is the acceleration. But it merely changes the direction of the velocity in this case, not its magnitude. So the kinetic energy does not change, and no work is done.
 
solved it, thanks!
 
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