Is the Proton-Electron Theory Disproved by Experimental Evidence?

  • Thread starter Thread starter Comanche
  • Start date Start date
  • Tags Tags
    Isospin
Comanche
Messages
7
Reaction score
0
Hi,

I read Georgi's Lie algebras in Particle Physics 2nd chap5 and have two questions.

1) In the beginning he mentioned Heisenberg regarded neutron is composed as proton and electron, the force between nucleons are exchanging electrons. My question is, what is the experimental evidence falsifies this idea (except proton proton scattering in accelerators)?

2) In p81, he built multiparticle states by successively adding creation operators
a^{\dagger}_{N,1/2,\alpha_1} \cdots a^{\dagger}_{N,1/2,\alpha_n} | 0 >

My question is, is that just a basis of multiparticle eigenstate of Hamiltonian? Imagine there is a vacuum. I first created a helium nuclei, then add a single electron. When I add the second electron, the helium electronic eigenstate will not be a tensor product of two single-electron state. The tensor product is just a two-electron (plus a nuclei) basis. Back to the equation of multiparticle state, is that just a basis?

Similarly for many hadrons, like u\bar{d}, is that a basis or a notation means the pion contains u and \bar{d}?

Thank you very much in advance
 
Physics news on Phys.org
Comanche said:
1) In the beginning he mentioned Heisenberg regarded neutron is composed as proton and electron, the force between nucleons are exchanging electrons. My question is, what is the experimental evidence falsifies this idea (except proton proton scattering in accelerators)?
QM does not allow bound states of proton+electron within that size and energy, and those electrons would disturb the "other" electrons in atoms.
 
If the neutron were a proton-electron bound state, what would be its spin? What is the neutron's spin?
 
Vanadium 50 said:
If the neutron were a proton-electron bound state, what would be its spin? What is the neutron's spin?

thanks! only the first question left...
 
Last edited:
well cloud chambers proved the existence of quarks thereby disproving the proton-electron theory if your asking for experimental evidence.
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
Back
Top