Is the Slope of the Wheelchair Ramp Too Steep for Young Children?

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The discussion revolves around determining if a newly installed wheelchair ramp for young children is too steep. The calculations show that the force required to move a child in a wheelchair up the ramp exceeds the maximum force of 50N that can be applied. Specifically, the calculated force needed is 55N, which indicates that the ramp's slope is indeed too steep. The participants confirm that overcoming both gravity and friction at this slope requires more force than what is safe for the intended users. Ultimately, the ramp's design does not meet the necessary safety standards for young children using wheelchairs.
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Homework Statement



There was a new wheelchair ramp installed at a nurserey. It was built for young children with wheelchairs to go up instead of the stairs and it was made to not be too difficult to get up. If the required force is not more than 50N like the testers say. If the weight of one child+wheelchair is 30kg, and the slope of the ramp is 5degrees, is the slope too steep? The friction with everything regarding wheels is by coefficient of uk = .10

Homework Equations



Fg=mg
Fnet=Fa-Ff-F||
F||=Fgsintheta
Fperpen=Fgcostheta

The Attempt at a Solution



I have found fg by using Fg=mg
Fg=30(9.8)
Fg=294.3

then I found the F||=Fgsintheta
F||=294.3sin5
F||=25.6

Fperpen=Fgcostheta
Fperpen=294.3cos5
Fperpen=293.2


So now I was thinking to use the Fnet=Fa-Ff-F||


But I don't know what to find or anything to actually know if its too step or not, I don't know if that above equation is correct.



thanks
 
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hi homevolend! :smile:

(have a mu: µ and a theta: θ and a degree: ° and try using the X2 icon just above the Reply box :wink:)
homevolend said:
I have found fg by using Fg=mg
Fg=30(9.8)
Fg=294.3

then I found the F||=Fgsintheta
F||=294.3sin5
F||=25.6

Fperpen=Fgcostheta
Fperpen=294.3cos5
Fperpen=293.2


So now I was thinking to use the Fnet=Fa-Ff-F||

yes, that's fine :smile:, except i don't understand what your Fa is

now use the normal force and µ to find the friction force :wink:
 
Ok I am still not sure if I am using the correct formula to do the Fnet.

I did Fnet=Fa-Ff-F||

Fnet=50-29.43-25.6

Fnet=14.7


But that does not seem correct, I do not think I am using the right formula, Then once I have the fnet I do not know how or what else to find to say if it is steep enough or not.
 
hi homevolend! :smile:

(just got up :zzz: …)
homevolend said:
I did Fnet=Fa-Ff-F||

Fnet=50-29.43-25.6

oh i see … Fa is the applied force

no, you're misunderstanding the question, Fa is not 50, Fa is the minimum force needed to keep the wheelchair moving …

so find what Fa is from your Fnet = 0 formula, and then answer yes/no is it > 50 (which would mean the slope is too steep)? :smile:
 
Got it I used the 0=Fa-Fk-F||

Got 55, so yes it is too steep because it cannot be more than 55.
"Can be no more than 50N" so does that mean its too steep?
 
homevolend said:
Got it I used the 0=Fa-Fk-F||

Got 55, so yes it is too steep because it cannot be more than 55.
"Can be no more than 50N" so does that mean its too steep?

Yup! :smile:

overcoming both gravity and friction would require 55 N, so the slope is too steep for someone who can only apply 50 N
 
Thanks for the help tim.
 

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