Is the Sum of Torques Zero in a System with Equal Forces and Moment Arms?

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In summary, the conversation discusses a case where two equal and opposite forces act on an object, causing it to rotate in a circular motion. The question is whether the sum of torques in this case would also be zero, and it is determined that it would be so, whether the forces are equal or not. The angle between the moment arms would not affect the answer. It is also noted that for the object to only move in a circular motion without linear acceleration, there must be a reaction force at the origin.
  • #1
Kaneki123
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Okay...I have a question.In the case described in the picture, the medium between the two forces, which would normally cause stationary or uniform circular motion, is not straight..The moment arm of each force is equal, and the forces are also equal...Now my question is, would the sum of torques in this case also be 0, or not?...Like in the sense that, if these forces were unequal (with equal distance from origin), there would be some clockwise or anticlockwise torque, and THEN if one of the forces was made equal to the other, then would the system's motion be uniform circular motion (Sum of torques=0)...
P.S: I intentionally did not write the angle between moment arms, as I thought that would not affect the answer
 
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  • #2
Kaneki123 said:
In the case described in the picture
You forgot the picture.
 
  • #3
Kaneki123 said:
Okay...I have a question.In the case described in the picture, the medium between the two forces, which would normally cause stationary or uniform circular motion, is not straight..The moment arm of each force is equal, and the forces are also equal...Now my question is, would the sum of torques in this case also be 0, or not?...Like in the sense that, if these forces were unequal (with equal distance from origin), there would be some clockwise or anticlockwise torque, and THEN if one of the forces was made equal to the other, then would the system's motion be uniform circular motion (Sum of torques=0)...
P.S: I intentionally did not write the angle between moment arms, as I thought that would not affect the answer
There is no picture. But if you are describing something like the bent arm on a phonograph then the forces at the endpoints are equal, opposite and act along a common line. The bent arm will be under a bending stress in addition to the pure longitudinal stress.

Angular momentum is conserved. Internal torques always sum to zero.
 
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Heres the picuture...I apologize for inconvenience
 

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  • #5
Kaneki123 said:
Now my question is, would the sum of torques in this case also be 0, or not?...Like in the sense that, if these forces were unequal (with equal distance from origin), there would be some clockwise or anticlockwise torque, and THEN if one of the forces was made equal to the other, then would the system's motion be uniform circular motion (Sum of torques=0)...
For equal forces at right angles to equal moment arms, one moment arm 90 degrees clockwise from its force and one 90 degrees counter-clockwise, yes. The sum of the torques would be zero.

If you changed one of the forces to get the system spinning and then made the forces equal again, yes. The rotation rate of the system would be constant.
 
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Kaneki123 said:
Okay...I have a question.In the case described in the picture, the medium between the two forces, which would normally cause stationary or uniform circular motion, is not straight..The moment arm of each force is equal, and the forces are also equal...Now my question is, would the sum of torques in this case also be 0, or not?...

Yes. The two torques have equal magnitude but opposite direction. Typically you would decide that clockwise (or anti-clockwise) was positive making the other negative. So they sum to zero.
Like in the sense that, if these forces were unequal (with equal distance from origin), there would be some clockwise or anticlockwise torque, and THEN if one of the forces was made equal to the other, then would the system's motion be uniform circular motion (Sum of torques=0)...
P.S: I intentionally did not write the angle between moment arms, as I thought that would not affect the answer

It doesn't. The two forces could even act on the same arm eg zero angle between them.

I note that both of the forces in your diagram have a downward component. If the object is to move in a circular manner around the pivot/origin and not accelerate downwards as well there must also be a reaction force on it at the pivot/origin. As drawn that must have an upward component so the net force is zero. In fact, if it only moves in a circle and doesn't have linear acceleration, at all times the net linear force must be zero. Eg the reaction force at the origin may rotate.
 
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I thank you all for your help...Much appreciated...
 

Related to Is the Sum of Torques Zero in a System with Equal Forces and Moment Arms?

1. What is torque?

Torque is a measure of the force that can cause an object to rotate around an axis. It is typically represented by the symbol "τ" and is measured in units of newton-meters (N·m) in the metric system.

2. How is torque calculated?

Torque is calculated by multiplying the force applied to an object by the distance from the axis of rotation to the point where the force is applied. It can be represented by the equation τ = F x r, where τ is torque, F is force, and r is the distance from the axis of rotation.

3. What are some real-life examples of torque?

Some examples of torque in everyday life include opening a door with a doorknob, tightening a screw with a screwdriver, and pedaling a bike.

4. How does torque affect rotational motion?

Torque plays a crucial role in rotational motion. The greater the torque applied to an object, the greater its rotational acceleration will be. Additionally, torque can also change the direction of an object's rotational motion.

5. What factors can affect torque?

The two main factors that can affect torque are the amount of force applied and the distance from the axis of rotation. Additionally, the angle at which the force is applied and the shape and size of the object can also impact torque.

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